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arlik [135]
3 years ago
6

In three year's time, Mr Sullivan will be 3 times as old as his daughter. Six years ago, he was 6 times as old as her. How old a

re they now?
Mathematics
1 answer:
Mkey [24]3 years ago
5 0
S=sullivan's age
d=daughter's age


in 3 years time (s+3 and d+3)
sulivan is 3 times as old as daughter
s+3=3(d+3)

6 years ago (s-6 and d-6)
he was 6 times as old
s-6=6(d-6)

expand

s+3=3d+9
s-6=6d-36
for 2nd equation, add 6 to both sides
s=6d-30
sub 6d+30 for s in other equation
6d-30+3=3d+9
6d-27=3d+9
minus 3d both sides
3d-27=9
add 27 both sides
3d=36
divide both sides by 3
d=12

sub back

s=6d-30
s=6(12)-30
s=72-30
s=42



Mr. Sullivan is 42 now
Daughter is 12 now
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-139

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(4×2^3 - 2 (-5) - 2×3^3)/4×(-5)^2 = ((4×2^3 - 2 (-5) - 2×3^3) (-5)^2)/4:

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2^3 = 2×2^2:

((4×2×2^2 - 2 (-5) - 2×3^3) 25)/4 - 16×2^2

2^2 = 4:

((4×2×4 - 2 (-5) - 2×3^3) 25)/4 - 16×2^2

2×4 = 8:

((4×8 - 2 (-5) - 2×3^3) 25)/4 - 16×2^2

3^3 = 3×3^2:

((4×8 - 2 (-5) - 23×3^2) 25)/4 - 16×2^2

3^2 = 9:

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| 3 | 2

+ | 1 | 0

| 4 | 2:

(42 - 54 25)/4 - 16×2^2

42 - 54 = -(54 - 42):

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| 5 | 4

- | 4 | 2

| 1 | 2:

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(-12)/4 = (4 (-3))/4 = -3:

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2^2 = 4:

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-75 - 16×4

-16×4 = -64:

-64 - 75

-75 - 64 = -(75 + 64):

-(75 + 64)

| 7 | 5

+ | 6 | 4

1 | 3 | 9:

Answer:  -139

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