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777dan777 [17]
3 years ago
12

PLEASE HELP ME ON THIS!!!!!!!!!! ~BRAINLIEST AVAILABLE THX

Mathematics
2 answers:
PIT_PIT [208]3 years ago
3 0
F(n)=6n+12
Hope this helps!
SashulF [63]3 years ago
3 0
We can see that this table has a slope of 6. If you remember, the slope-intercept form is y = mx + b, where m is the slope. If we plug that in we have:
f(n) = 6n+b

b has to be a number that satisfies every value. If we plug in 1 for n, then right now we will be left with:
18 = 6(1) + b

Solving for b, we get:
b = 12

We have our final explicit function in terms of n (your answer):
f(n) = 6n + 12

Or, you can write this as:
f(n) = 6(n+2)
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Ivan
Company B offers the lowest price.

Company A:
32.50/2.5 =
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Company B:
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3 0
3 years ago
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Help! <br> work and answer please<br><br> -2+b&lt;3
Dovator [93]

Answer:

b < 5

Step-by-step explanation:

-2+b<3

Add 2 to each side

-2+2+b<3+2

b < 5

8 0
3 years ago
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Find the slope of a line perpendicular to 2x-y-16
Alekssandra [29.7K]

put the equation 2x - y = 16 in the form of y = mx + c

2x - y = 16

2x = 16 + y

y = 2x - 16

the slope of this line is 2. the slope of a line perpendicular to it would be the negative reciprocal of 2. in other words, it would multiply with 2 to give -1.

you can form this equation with that info

2x = -1

x = -1/2

OR

you can flip and change the sign (numerator) of 2/1

2/1

= -1/2

6 0
3 years ago
I have been stuck on some accounting math which are about 2/3 pages long. I just procrastinate every time I try to practice thos
rjkz [21]

Answer:

Get rid of distractions that makes you procrastinate.

Step-by-step explanation:

Focus doing your practices. To focus, you need to get rid of any distractions that make you procrastinate.

As an example, if it's your phone/social media. Try to make it silent/put it away from you when you're going to do your practices. (recommended to give to parents or put in other room until you finish your works)

This is just my suggestion. It works for some people.

4 0
3 years ago
(30PTS) What are the slopes of the asymptotes of a hyperbola with equation x^2/2^2-y^2/6^2=1
Akimi4 [234]

Answer:

2x2−3y2=6or2x26−3y26=1 or. x23−y22=1or(x−0)2(√3)2−(y−0)2(√2)2=1. This is standard form of the equation of a hyperbola with center.

Step-by-step explanation:

c2 = a2 + b2. Every hyperbola has two asymptotes. A hyperbola with a horizontal transverse axis and center at (h, k) has one asymptote with equation y = k + (x - h) and the other with equation y = k - (x - h).

4 0
3 years ago
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