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3 years ago

10

Divide (x^2-16/x-1)/x+4

1 answer:

GenaCL600 [577]3 years ago

6 0

$\bf \cfrac{\quad \frac{\stackrel{\textit{}}{x^2-16}}{x-1}\quad }{x+4}\implies \cfrac{\quad \frac{\stackrel{\textit{difference of squares}}{x^2-4^2}}{x-1}\quad }{x+4}\implies \cfrac{\quad \frac{(x-4)(x+4)}{x-1}\quad }{x+4}
\\\\\\
\cfrac{\quad \frac{(x-4)(x+4)}{x-1}\quad }{\frac{x+4}{1}}\implies \cfrac{(x-4)\underline{(x+4)}}{x-1}\cdot \cfrac{1}{\underline{x+4}}\implies \cfrac{x-4}{x-1}$

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