I can't exactly SHOW you where to put the numbers, but I can teach you the process of how you'd do it.
First off, label your number line from 0-15, as it is the simplest. (You'd be counting by 1 per each line). Then, follow this process:
1) Look at the first digit of your value. Place your number according to your first digit. (So, you'd put 0.365 at the 0 line and 3.521 at the 3 line)
2) Look at the second digit of your value. Imagine that between the two main lines (0-1 and 3-4) that there is 10 smaller lines. Then, you can place your number according to your second digit. (So, you'd put 0.365 at the 0.3 line and 3.521 at the 3.5 line).
3) Look at the third digit of your value. Imagine that between the two smaller lines (0.3-0.4 and 3.5-3.6) that there is 10 smaller lines. Then, you can place your number according to your third digit. (So, you'd put 0.365 at the 0.36 line and 3.521 at the 3.52 line).
4) Look at the fourth digit of your value. Imagine that between the two even smaller lines (0.36-0.37 and 3.52-3.53) that there is 10 smaller lines. Then, you can place your number according to your fourth digit. (So you'd place 0.365 at the 0.365 line and 3.521 at the 3.521 line)
Answer:
Step-by-step explanation:
3x(x^2+4)
=3x^2+12x
Answer:
12
Step-by-step explanation:
let x be the number of men
4:7 = x:21
4/7 = x/21
7x = 84
x = 12
Answer:
y=5 and x=4
Step-by-step explanation:
So,the diagonals of a parallelogram bisect each other..
therefore,we have our two eqn
4x-2=3y-1------------(i)
3y-3=3x
or,y-1=x----------(ii)
Now,simply substitute value of x in eqn (i)
4(y-1)-2=3y-1
or,4y-4-2=3y-1
or,y=5
Again,substitute y=5 in eqn (ii)
5-1=x
therefore,
x=5
Hope it helps you!!!
The answer would be B. If you want to FIND how many points a person has, you put the "p" on its own on the left of the equation, and since every field goal (f) you score is worth 3 points, just multiply "f" by 3 (3f).
For example, if someone scored 5 field goals in a game, to find how many points they totalled, just plug in the 5 for "f":
1. Get equation:
p = 3f
2. Plug in field goals for "f":
p = 3(5)
3. Solve:
p = 15