Question

Graph the line given by 2x+y=1 and the circle given by x²+y²=10.Find all solutions to the system of equations. Verify your result both algebraically and graphically.

Answer 1

Answer:

(1.8, -2.6) and (-1, 3)

Step-by-step explanation:

$2x+y=1$

$x^2+y^2=10$

From the first equation

$y=1-2x$

Applying to the second equation

$x^2+(1-2x)^2=10\\\Rightarrow x^2+1+4x^2-4x=10\\\Rightarrow 5x^2-4x-8=0$

Solving the equation we get

$x=\frac{-\left(-4\right)+\sqrt{\left(-4\right)^2-4\cdot \:5\left(-9\right)}}{2\cdot \:5}, \frac{-\left(-4\right)-\sqrt{\left(-4\right)^2-4\cdot \:5\left(-9\right)}}{2\cdot \:5}\\\Rightarrow x=1.8, -1$

At x = 1.8

Applying in first equation

$2\times 1.8+y=1\\\Rightarrow y=1-3.6\\\Rightarrow y=-2.6$

At x = -1

Applying in first equation

$2\times -1+y=1\\\Rightarrow y=1+2\\\Rightarrow y=3$

∴ The circle and line intersect at points (1.8, -2.6) and (-1, 3)