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3 years ago

A triangle has side lengths of 12cm, 35cm, and 37cm. classify it as acute,obtuse, or right

Mathematics

1 answer:

Nady [450]3 years ago

7 0

When given 3 triangle sides, to determine if the triangle is acute, right or obtuse:

1) Square all 3 sides.

2) Sum the squares of the 2 shortest sides.

3) Compare this sum to the square of the 3rd side.

if sum > 3rd side² Acute Triangle

if sum = 3rd side² Right Triangle

if sum < 3rd side² Obtuse Triangle

1) 144

1,225

1,369

144 + 1,225 = 1,369

Therefore, it is a right triangle.

Source:

http://www.1728.org/triantest.htm

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Where will her cut be located? Round to the nearest tenth. x = (StartFraction m Over m + n EndFraction) (x 2 minus x 1) + x 1 A

Arte-miy333 [17]

Answer:

The correct answer is 25.2 in.

Step-by-step explanation:

It is given that number line goes from 0 to 60 which can be used to represent a ribbon of length = 60 inches.

2 inches of the ribbon are frayed so actual length = 58 inches

Please refer to the attached image for the ribbon.

A is at 0

C is at 60

B is at 2

P is the point to divide the remaining ribbon in the ratio 2:3.

Part AB of the ribbon is frayed.

BP: PC = 2:3

Let BP = 2 $x$ and PC = 3 $x$

Now, BP + PC = BC = 58 = 2 $x$ + 3 $x$ = 5 $x$

So,

$5x =58\\\Rightarrow x =11.6$

BP = $2\times x = 2 \times 11.6 = 23.2\ inches$

Location of the Cut = 2 + 23.2 = 25.2 inches

Alternatively, we can use the formula directly:

$x = \dfrac{m} {m + n } (x_2 - x_1) + x_1$

$x_1 = 2\\x_2 = 60$

m: n is the ratio 2:3

$x = \dfrac{2} {2 +3 } (60- 2) + 2\\\Rightarrow 0.4 (58 )+2\\\Rightarrow 23.2+2 \\\Rightarrow \bold{25.2\ inches}$

5 0

3 years ago

Read 2 more answers

Solve a triangle when A=40 B = 50 , and C=14.

tekilochka [14]

Answer:

(c)=81°, a=9.1, b=12.

Step-by-step explanation:

m<A=40°, m<B=59

m<C=180-(40+59)=81

c=14

6 0

2 years ago

Blood type AB is the rarest blood type, occurring in only 4% of the population in the United States. In Australia, only 1.5% of

Umnica [9.8K]

Answer:

a. X is a binomial random variable with n = 50 and p = 0.04

b. Y is a binomial random variable with n = 40 and p = 0.015

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

X: the number of US residents (out of 50) with blood type AB.

Blood type AB is the rarest blood type, occurring in only 4% of the population in the United States

This means that $p = 0.04, n = 50$

Y: the number of Australians (out of 40) with blood type AB.

In Australia, only 1.5% of the population has blood type AB.

This means that $p = 0.015, n = 40$

Z: the total number of individuals (out of 90) with blood type AB.

Here

$n = 90, p = 0.04*\frac{50}{90} + 0.015*\frac{40}{90} = 0.0289$

Which of the following is true about the random variables X, Y, and Z?

Options a and b are true, while c is false.

7 0

3 years ago

Drag steps in the given order to evaluate this expression. (−5)(2)−2(−3)+3 ( -5 )( 2 ) - 2 ( -3 ) + 3

Snowcat [4.5K]

(−5)(2)−2(−3)+3 ( -5 )( 2 ) - 2 ( -3 ) + 3

=-10+6-30+6+3

=15-40

=-25

6 0

3 years ago

I need to know the answer I’m working on rational numubers

lesya [120]

Answer:

Fraction Form: $\frac{11}{24}$

Decimal Form: 0.4583

Step-by-step explanation:

Apply the fraction rule: $\frac{-a}{b} = - \frac{a}{b}$

$\frac{-5}{12} = - \frac{5}{12}$

$- \frac{5}{12} + \frac{7}{8}$

Least Common Multiple (LCM) of 12 and 8: 24

$- \frac{5}{12} x \frac{2}{2} = - \frac{10}{24} \\\\\frac{7}{8} x \frac{3}{3} = \frac{21}{24} \\\\- \frac{10}{24} + \frac{21}{24}$

Apply the fraction rule:

$\frac{a}{c} + \frac{b}{c}= \frac{a + b}{c}\\\\\frac{-10 + 21}{24} \\\\-10 + 21 = 11\\\\\frac{11}{24}$

3 0

1 year ago