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sattari [20]
3 years ago
14

Where will her cut be located? Round to the nearest tenth. x = (StartFraction m Over m + n EndFraction) (x 2 minus x 1) + x 1 A

number line goes from 0 to 60. A line is drawn from 2 to 60. Genevieve is cutting a 60-inch piece of ribbon into a ratio of 2:3. Since 2 inches are frayed at one end of the ribbon, she will need to start 2 inches in. This is indicated as 2 on the number line
25.2 in.

29.4 in.

35.1 in.

40.7 in.

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
5 0

Answer:

The correct answer is 25.2 in.

Step-by-step explanation:

It is given that number line goes from 0 to 60 which can be used to represent a ribbon of length = 60 inches.

2 inches of the ribbon are frayed so actual length = 58 inches

Please refer to the attached image for the ribbon.

A is at 0

C is at 60

B is at 2

P is the point to divide the remaining ribbon in the ratio 2:3.

Part AB of the ribbon is frayed.

BP: PC = 2:3

Let BP = 2x and PC = 3x

Now, BP + PC = BC = 58 = 2x + 3x = 5x

So,

5x =58\\\Rightarrow x =11.6

BP = 2\times x = 2 \times 11.6 = 23.2\ inches

Location of the Cut = 2 + 23.2 = <em>25.2 inches</em>

<em></em>

Alternatively, we can use the formula directly:

x = \dfrac{m} {m + n } (x_2 - x_1) + x_1

x_1 = 2\\x_2 = 60

m: n is the ratio 2:3

x = \dfrac{2} {2 +3 } (60- 2) + 2\\\Rightarrow 0.4 (58 )+2\\\Rightarrow 23.2+2 \\\Rightarrow \bold{25.2\ inches}

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Sum of positive roots of the equation (x2 - 12x + 35) (x2 + 10x + 24) = 504 is
Digiron [165]

Answer:

(3)11

Step-by-step explanation:

We are given that

(x^2-12x+35)(x^2+10x+24)=504

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x^2(x^2+10x+24)-12x(x^2+10x+24)+35(x^2+10x+24)=504

x^4+10x^3+24x^2-12x^3-120x^2-288x+35x^2+350x+840=504

x^4-2x^3-61x^2+62x+840-504=0

x^4-2x^3-61x^2+62x+336=0

Factor of 336

2,3,4,6,8,7,

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2^4-2^4-61(2^2)+62(2)+336\neq0

x=2 is not the root of equation

x=-2

(-2)^4-2(-2)^3-61(-2)^2+62(-2)+336=0

Hence x=-2 is the root of equation.

x+2 is a factor of equation.

x=3

3^4-2(3^3)-61(3^2)+62(3)+336=0

Therefore, x=3  is the root of equation.

(x+2)(x-3)(x^2-x-56)=0

(x+2)(x-3)(x^2-8x+7x-56)=0

(x+2)(x-3)(x(x-8)+7(x-8))=0

(x+2)(x-3)(x-8)(x+7)=0

x-8=0\implies x=8

x+7=0\implies x=-7

Positive roots are 3 and 8

Sum of positive roots=3+8=11

Option (3) is true.

4 0
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Step-by-step explanation:

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4 0
4 years ago
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Answer:

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3 years ago
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