Question

There are fifteen teams in a high school baseball league. How many different orders of finish are possible for the first four ​positions?
There are
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nothing different orders of finish for the first four positions.

Answer 1

There are 32,760 different orders for the first four positions.

This is a permutation where repetition is not allowed; the formula for that is:

$_nP_r=\frac{n!}{(n-r)!}$

For our problem, we have:
$_{15}P_4=\frac{15!}{(15-4)!}=\frac{15!}{11!}=32760$