Rule 1: Simplify all operations inside parentheses.
Rule 2: Perform all multiplications and divisions, working from left to right.
Rule 3: Perform all additions and subtractions, working from left to right.
Rule 1: Simplify all operations inside parentheses.
Rule 2: Simplify all exponents, working from left to right.
15+26s-6=25s-9
26s+9=25s-9
s+9=-9
s=-18
Answer:
The small balloon bouquet uses 7 balloons and the large one uses
18 balloons.
Step-by-step explanation:
Let's say that small balloon bouquets are S and large balloon bouquets are L. For the graduation party the employee assembled 6 small bouquets and 6 large bouquets, the total number of balloon used is 150. To put the sentence into an equation will be:
6S + 6L= 150
S+L= 25 ----> 1st equation
For Father's Day, the employee uses 6 small bouquet and 1 large bouquet, the total number of balloons used is 60. The equation will be:
6S + 1L= 60
1L= 60- 6S ----> 2nd equation
We can solve the number of small balloon bouquet by substitute the 2nd equation into 1st. The calculation will be:
S+L = 25
S+ (60-6S)= 25
-5S= 25-60
-5S= -35
S= -35/-5
S=7
Then we can find L by substitute S value to 1st or 2nd equation.
S+L=25
7+L=25
L=18
Answer:
x₁ = 20 x₂ = 0
z (min) = 20
Step-by-step explanation:
According to the problem statement:
Let´s call
Objective quiz = x₁ Recall quiz = x₂
First constraint
Quantity of quizzes at least 15
x₁ + x₂ ≥ 15
Second constraint:
Preparation time at least 300 minutes, then
15*x₁ + 30*x₂ ≥ 300
Third constraint
Average score at least 85 points
7*x₁ + 5*x₂ ≥ 85
General constraint x₁ ≥ 0 x₂ ≥ 0
Objective function z is:
z = 1* x₁ + 1,5*x₂ to minimize
The model:
z = x₁ + 1,5x₂ to minimize
Subject to
x₁ + x₂ ≥ 15
15*x₁ + 30*x₂ ≥ 300
7*x₁ + 5*x₂ ≥ 85
Using Atozmax (online solver) we find
x₁ = 20 x₂ = 0
z (min) = 20
Answer:
The value of the expression is - 5.
Step-by-step explanation:
(-2x +10) - (-6x + 5y + 12) + (x +8y - 16)=
-2x+10+6x-5y-12+x+8y-16=
(-2x+6x+x)+(-5y+8y)+(10-12-16)=
5x+3y-18
if x=5 and y=-4 then
5*5+3*(-4)-18=25-12-18=25-30=-5
