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3 years ago

EXPERTS/ACE/GENIUSES

Mathematics

1 answer:

Naddik [55]3 years ago

6 0

1SF = 1 1/2 = 1.5
centered at origin

answer is
figures MNO and PNQ

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If 18 bags of popcorn is $13.45 then how much money is only 1 bag of popcorn?

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One bag of popcorn is 1.33

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3 years ago

9. Wade has 126 inches of 1-inch wide bias tape for a border

viktelen [127]

Answer:

Let 'x' represent the width.

2*48 + 2x = 126

x = 15 in

The maximum width could be 15 inches.

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3 years ago

A solution is tested and found to have a pH of 1. The solution is A. strongly acidic. B. strongly basic. C. weakly basic. D. wea

Trava [24]

When a solution has Ph of 1 in it

it is highly acidic

So your answer would be A) Strongly acidic

Hope this helped! good luck (:

7 0

3 years ago

Read 2 more answers

an actor will earn d dollars this year. His agent Collects a Commission of 10% of all his earnings. which expression shows how m

Naya [18.7K]

Answer: d - (d x .1)

Step-by-step explanation: The expression that will show how much the actor will earn is d - (d x .1). D is the actor’s earnings and d x .1 is the commission of their agent.

7 0

3 years ago

One of your peers claims that boys do better in math classes than girls. Together you run two independent simple random samples

JulijaS [17]

Answer:

Step-by-step explanation:

Hello!

To test if boys are better in math classes than girls two random samples were taken:

Sample 1

X₁: score of a boy in calculus

n₁= 15

X[bar]₁= 82.3%

S₁= 5.6%

Sample 2

X₂: Score in the calculus of a girl

n₂= 12

X[bar]₂= 81.2%

S₂= 6.7%

To estimate per CI the difference between the mean percentage that boys obtained in calculus and the mean percentage that girls obtained in calculus, you need that both variables of interest come from normal populations.

To be able to use a pooled variance t-test you have to also assume that the population variances, although unknown, are equal.

Then you can calculate the interval as:

[(X[bar]_1-X[bar_2) ± $t_{n_1+n_2-2;1-\alpha /2}$ * $Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }$ ]

$Sa= \sqrt{\frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2} } = \sqrt{\frac{14*(5.6^2)+11*(6.7^2)}{15+12-2} }= 6.108= 6.11$

$t_{n_1+n_2-2;1-\alpha /2}= t_{15+12-2;1-0.05}= t_{25;0.95}= 1.708$

[(82.3-81.2) ± 1.708* (6.11* $\sqrt{\frac{1}{15}+\frac{1}{12} }$ ]

[-2.94; 5.14]

Using a 90% confidence level you'd expect the interval [-2.94; 5.14] to contain the true value of the difference between the average percentage obtained in calculus by boys and the average percentage obtained in calculus by girls.

I hope this helps!

3 0

3 years ago