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Dahasolnce [82]
4 years ago
12

Joe bought 5.8 pounds of grapes to have as a snack with his 10 friends.If he shares his grapes evenly,how many pounds of grapes

will each of his friends get?
Mathematics
2 answers:
yaroslaw [1]4 years ago
6 0
Divide 5.8 by 10. Answer is .58 pound
astraxan [27]4 years ago
4 0

Answer: Each friend will get 0.527 pound of grapes.

Step-by-step explanation:

We are given that Joe bought 5.8 pounds of grapes to have as a snack with his 10 friends.

Total persons including Joe = 10+1= 11

If he shares his grapes evenly, then by division operation , we have

Number of pounds of grapes will each of his friends get will be

5.8\div11\approx0.527 pounds

Therefore, each friend will get 0.527 pounds of grapes.

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Observe the expression below and select the true statement(s).
DENIUS [597]

Answer: The 9 in the second term is a coefficient that is true. I think that is the only thing that is true. There may be one more thing that is true.

The 10 in the third term is not  a coefficient.

The 2 is not a constant

the x is not an exponent.

those are the ones that I'm sure about.

Please correct anything if i'm wrong.

:)

7 0
3 years ago
A jewelry store purchases necklaces for n dollars each. The necklaces are then marked up by 20%, and costumers are charged 5% sa
Aleksandr [31]

Answer:

Step-by-step explanation:

Cost price = $n

Mark up price = selling price- cost price

= (20% × $n)

Selling price = $n + (20% × $n)

Sales tax = 5% × ($n + (20% × $n))

Total cost = selling price + sales tax

Total cost = $n + (20% × $n) + 5% × $n + (20% × $n)

= 1.2 × $n + 0.06 × $n

= 1.26 × $n.

8 0
3 years ago
The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co
Alona [7]

Answer:

95% Confidence interval for the variance:

3.6511\leq \sigma^2\leq 34.5972

95% Confidence interval for the standard deviation:

1.9108\leq \sigma \leq 5.8819

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

s^2=2.89^2=8.3521

The confidence interval for the variance is:

\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128

Then, the confidence interval can be calculated as:

\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819

6 0
3 years ago
The cargo carrying part of Billy‘s truck has a length of 8.3 m a width of 3 m and a height of 4.2 m. What is the maximum volume
madam [21]
You're really just finding the volume of the cargo-carry part.

V= L x W x H

V= 8.3m x 3m x 4.2m

V= 104.58 m3 or 105 m3 (rounded)

ANSWER: The maximum volume of sand Billy's truck can carry is about 105 m3.
8 0
3 years ago
What is the sum of negative 3 and negative 9
LenaWriter [7]
The answer would be -12
5 0
3 years ago
Read 2 more answers
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