Answer:
gamete
Explanation:
is the cell that is the half of the normal cell and is the starting cell of the embrion
Answer:
frequency of d allele = 0.635
Explanation:
If p = frequency of dominant allele and q= frequency of recessive allele
According to Hardy-Weinberg equilibrium:
p + q =1 and p² + 2pq + q² = 1
where p² = frequency of homozygous dominant genotype
q²= frequency of homozygous recessive genotype
and 2pq= frequency of heterozygous genotype
Here,
q² = d² = 131/325= 0.403
so q= d= √0.40 = 0.6348 = 0.635
Hence frequency of d allele = 0.635
