Idk what the answer is but dab if u see this
Answer:
462ways
Step-by-step explanation:
This Is a combination problem, we we are expected to determine the number of possible ways of selecting the numbers of staffs for a business trip
C(n, r) were n= 11
r=5
C(n, r) = n!/(n-r)! r!
C(n, r) = 11!/(11-5)! 5!
C(n, r) = 11!/(6)! 5!
C(n, r) = 11*10*9*8*7*6!/(6)! 5*4*3*2*1
C(n, r) = 11*10*9*8*7/5*4*3*2*1
C(n, r) = 55440/120
C(n, r) = 462
The number of possible ways is 462
Answer:
x < 2 ∪ x > 3
Step-by-step explanation:
Rewrite 3x - 4 > 5 as 3x > 9. This tells us that x must be greater than 3.
Rewrite 8x - 10 < 6. Thus, 8x < 16 and x < 2.
The "solution set" is thus all real numbers to the left of 2 OR to the right of 3.
I honestly dont know what to solve?
