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ArbitrLikvidat [17]
3 years ago
5

Please help round to the nearest tenth

Mathematics
1 answer:
Romashka [77]3 years ago
6 0

Answer:

a = 4.6

b = 4.2

Step-by-step explanation:

to find a, use cos:

⇒ cos = \frac{adjacent}{hypothenuse}

⇒ cos 30 = \frac{13}{a}

cos of 30 is 0.154

⇒ 0.154 = \frac{13}{a}

multiply 13 on both sides:

⇒ 0.154 x 13 = \frac{13}{a} x 13

⇒ 4.62 = a

round to the nearest tenth:

⇒ 4.62 = 4.6

⇒ a = 4.6

to find b, use tan:

⇒ tan = \frac{opposite}{adjacent}

⇒ tan 60 = \frac{b}{13}

tan of 60 is 0.320

⇒ 0.320 = \frac{b}{13}

multiply 13 on both sides:

⇒ 0.320 x 13 = \frac{b}{13} x 13

⇒ 4.16 = b

round to the nearest tenth:

⇒ 4.16 = 4.2

⇒ b = 4.2

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Answer:

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7 0
3 years ago
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2(x-3) = (x-1) + 7<br><br> Please show your steps!!
andre [41]
Simplify the equation.

First, distribute the 2 in the left side of the equation.
Resulting in: 2x-6 = (x-1) + 7

Second, remove the parentheses form the right side of the equation (there is nothing to distribute there).
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Now simplify the right side of the equation by subtracting the 1 from the 7.
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3 years ago
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#5
Colt1911 [192]

Answer:

1.5 seconds

Step-by-step explanation:

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Calculus question....does anyone know how to solve this?
iogann1982 [59]
h(x)=(f\circ g)(x)
\sqrt{x+5}=\sqrt{g(x)+2}
x+5=g(x)+2
g(x)=x+3

Just to check this is correct:

(f\circ g)(x)=f(g(x))=f(x+3)=\sqrt{(x+3)+2}=\sqrt{x+5}=h(x)
6 0
3 years ago
PLEASEEEEE HELPPPPP!!!!
Dmitry_Shevchenko [17]

Step One

Find AM

Formula

AM = MN - AN

Givens

MN = 67.2

AN = 32

Solution

AM - 67,2 - 32

AM = 35.2

Step Two

Set up a solution

67.2/35.2 = 81.9/x            Cross Muliply

67.2 * x   =    81.9 * 35.2   Combine the right

67.2 * x = 2882.88            Divide by 67.2

x = 2882.88/67.2

x = 42.9                             Answer

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