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ArbitrLikvidat [17]
3 years ago
5

Please help round to the nearest tenth

Mathematics
1 answer:
Romashka [77]3 years ago
6 0

Answer:

a = 4.6

b = 4.2

Step-by-step explanation:

to find a, use cos:

⇒ cos = \frac{adjacent}{hypothenuse}

⇒ cos 30 = \frac{13}{a}

cos of 30 is 0.154

⇒ 0.154 = \frac{13}{a}

multiply 13 on both sides:

⇒ 0.154 x 13 = \frac{13}{a} x 13

⇒ 4.62 = a

round to the nearest tenth:

⇒ 4.62 = 4.6

⇒ a = 4.6

to find b, use tan:

⇒ tan = \frac{opposite}{adjacent}

⇒ tan 60 = \frac{b}{13}

tan of 60 is 0.320

⇒ 0.320 = \frac{b}{13}

multiply 13 on both sides:

⇒ 0.320 x 13 = \frac{b}{13} x 13

⇒ 4.16 = b

round to the nearest tenth:

⇒ 4.16 = 4.2

⇒ b = 4.2

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saul85 [17]

\large\underline{\sf{Solution-}}

<u>Let us assume that:</u>

\sf \longmapsto x =  \sqrt{6 +  \sqrt{6 +  \sqrt{6 + ... \infty } } }

We can also write it as:

\sf \longmapsto x =  \sqrt{6 +  x }

Squaring both sides, we get:

\sf \longmapsto  {x}^{2}  =6 +  x

\sf \longmapsto  {x}^{2} - x - 6  =0

By splitting the middle term:

\sf \longmapsto  {x}^{2} - 3x + 2x - 6  =0

\sf \longmapsto x(x - 3) + 2(x - 3 ) =0

\sf \longmapsto (x+ 2)(x - 3 ) =0

<u>Therefore:</u>

\longmapsto\begin{cases} \sf (x+ 2) =0 \\ \sf (x - 3) = 0 \end{cases}

\sf \longmapsto x =  - 2,3

<u>But x cannot be negative. </u>

\sf \longmapsto x = 3

Therefore, the value of the expression is 3.

\large\underline{\sf{Verification-}}

Given:

\sf\longmapsto x=3

We can also write it as:

\sf\longmapsto x = \sqrt{9}

\sf\longmapsto x = \sqrt{6+3}

\sf\longmapsto x = \sqrt{6 + \sqrt{9}}

\sf\longmapsto x = \sqrt{6 + \sqrt{6+3}}

\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{9}}}

\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+3}}}

This pattern will continue.

\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+...\infty}}}

7 0
3 years ago
What is the range for the scores: 13, 23, 60, 46, 53, 75.
vova2212 [387]
Hello there.

Question: <span>What is the range for the scores: 13, 23, 60, 46, 53, 75.

Answer: Range is the largest value minus the smallest answer:
75 - 13 = 62.
The range is 62.

Hope This Helps You!
Good Luck Studying ^-^</span>
6 0
3 years ago
Whats balck and white and has lot or problems?
xxTIMURxx [149]

Answer:

A math test

Step-by-step explanation:

5 0
3 years ago
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Answer:

1/4

Step-by-step explanation:

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7 0
3 years ago
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If x-y=1 and xy= 56 then find the value of x+y​
tester [92]

Answer:

x + y = ±15

Step-by-step explanation:

Step 1: Write out systems of equations

x - y = 1

xy = 56

Step 2: Rearrange 1st equation

x = y + 1

Step 3: Substitution

(y + 1)y = 56

Step 4: Distribute

y² + y = 56

Step 5: Solve for <em>y</em>

y² + y - 56 = 0

(y - 7)(y + 8) = 0

y = -8, 7

Step 6: Plug in <em>y </em>to find <em>x</em>

x - 7 = 1

x = 8

x - (-8) = 1

x + 8 = 1

x = -7

Step 7: Find answer

x + y = ?

8 + 7 = 15

-7 + -8 = -15

So both 15 and -15 could be the answer.

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