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Natasha_Volkova [10]

3 years ago

12

a contractor estimated that her expenses for a construction project would be $700,000 and $750,000. She has already spent $496,0

00. How much more can she spend and remain within her estimate?

1 answer:

Alborosie3 years ago

4 0

By doing 750,000-496,000 you will get $254,000

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Can someone help me please

ahrayia [7]

Answer:

hieght at left is 24+1

and right is 25 both are equal now so h=25

base=8

area of triangle 1/2×b×h

1/2×8×25=100

7 0

3 years ago

Read 2 more answers

Jlenok [28]

3. 5/8 and 30/48 because 5 can go into 30 and 8 can go into 48

6 0

3 years ago

Five years back, Michael's age was 2/3 the age of James. After ten years he will be 5/6 of the age of James. What are the equati

irakobra [83]

I find it easier to start from scratch and write out the equations, then compare them with the given equations.

Let m and j represent the ages of the two boys. Then m-5=(2/3)(j-5)
Also, in ten years: m+10 = (5/6)j.

Let's solve this system: Mult the first eqn by 3 to remove the fraction:
3(m-5) = 2(j-5), or 3m - 15 = 2j -10. Next, mult. the 2nd eqn by 6 to remove the fraction: 6m+60 = 5j.

Our two equations are (at this point) 3 m - 15 = 2j - 10 and
6m +60 = 5j

Let's mult. the first equation by -2, so as to obtain the coefficient -6 for m:

-6m + 30 = -4j + 10
6m + 60 = 5j
---------------------------
90 = j + 10, so j = 80 (wow!)

Let's now find m: 6m + 60 = 5(80), or 6m = 400+60 = 460

Then m = 76 2/3.

We must check our solution (m = 76 2/3, j = 80):

Let's subst. these values into m-5=(2/3)(j-5)

Does 76 2/3 - 5 = (2/3)(80) - 10/3?

Does 76 2/3 - 15/3 = 160/3 - 10/3?

Does 76 - 15 = 160 - 10 No. So something's wrong here.

Going back to the problem statement:

<span>x-5=2/3(y-5) and x+10=5/6(y+10) seems correct!

Mike's age 5 years ago was x-5, and james' age 5 years ago was y-5. The multiplier (2/3) is also correct.

Mikes age 10 years from now will be x+10, and james' y+10.

The first answer set is the correct one.</span>

7 0

3 years ago

Troy is searching for a new home. He’ll need to take out a mortgage once he finds a house. Before visiting the bank, Troy decide

max2010maxim [7]

Answer:

Troy could have been a victim of identity theft , and he should check his credit report more often to avoid being surprised in the future.

Step-by-step explanation:

5 0

3 years ago

Based on the Fundamental Theorem of Algebra, how many complex roots does each of the following equations have? Write your answer

Galina-37 [17]

According to the fundamental theorem of algebra, <span>every polynomial of degree n has n complex zeroes.

Part A:

Given

$x(x^2-4)(x^2+16)=0 \\ \\ \Rightarrow x(x^4+12x^2-64)=0 \\ \\ \Rightarrow x^5+12x^3-64x=0$

Thus, the given polynomial is of degree 5 and hence has 5 omplrex roots.

Part B:

Given

$(x^2+4)(x+5)^2 = 0 \\ \\ \Rightarrow(x^2+4)(x^2+10x+25)=0 \\ \\ \Rightarrow x^4+10x^3+25x^2+4x^2+40x+100=0 \\ \\ \Rightarrow x^4+10x^3+29x^2+40x+100=0$

Thus, the polynomial is of degree 4 and hence has 4 complex roots.

Part C:

Given

$x^6-4x^5-24x^2+10x-3=0$

Thus, the given polynomial is of degree 6 and hence has 6 complex roots.

Part D:

Given

$x^7+128=0$

</span><span>Thus, the given polynomial is of degree 7 and hence has 7 complex roots.</span>

Part E:

Given

$(x^3+9)(x^2-4)=0 \\ \\ \Rightarrow x^5-4x^3+9x^2-36=0$

Thus, the given polynomial is of degree 5 and hence has 5 complex roots.

4 0

3 years ago