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Natasha_Volkova [10]

3 years ago

12

a contractor estimated that her expenses for a construction project would be $700,000 and $750,000. She has already spent $496,0

00. How much more can she spend and remain within her estimate?

1 answer:

Alborosie3 years ago

4 0

By doing 750,000-496,000 you will get $254,000

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in science class, Marco recorded numbers. from an experiment as 12.87 12.13 12.5 and 12.08 which numbers are closer to 12 ? whic

Ludmilka [50]

Answer:

12.87, 12.5 is closer to 13

12.08, 12.13 is closer to 12

Step-by-step explanation:

Least to Greatest:

12

12.08

12.13

12.5

12.87

13

4 0

3 years ago

What is 0.36666...(6 is repeating) as a fraction. Show your work

shtirl [24]

0.366<span> = 11/30 </span>
0.366<span> = 11/30 </span>
0.366<span> = 122/333

</span>

7 0

3 years ago

What is the y-intercept of the line

pychu [463]

My guess would be -54 because we are starting with -54

4 0

3 years ago

The following data show the average retirement ages for a random sample of workers in the United States and a random sample of w

SSSSS [86.1K]

Answer:

$t \approx 2.639$

Step-by-step explanation:

Given

$\begin{array}{ccc}{} & {USA\ 1} & {Japan\ 2} & {\bar x} & {64.6} & {67.5} &{n} & {30} & {30} & {\sigma} & {4.0} & {4.5} \ \end{array}$

See attachment for data

Required

Determine the test statistic

The test statistic is calculated using:

$t = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}}}$

So, we have:

$t = \frac{64.6 - 67.5}{\sqrt{\frac{4.0^2}{30} + \frac{4.5^2}{30}}}$

$t = \frac{64.6 - 67.5}{\sqrt{\frac{16.00}{30} + \frac{20.25}{30}}}$

$t = \frac{64.6 - 67.5}{\sqrt{\frac{16.00+20.25}{30}}}$

$t = \frac{64.6 - 67.5}{\sqrt{\frac{36.25}{30}}}$

$t = \frac{-2.9}{\sqrt{1.2083}}$

$t = \frac{-2.9}{1.099}$

$t \approx -2.639$

The absolute value is:

$t \approx 2.639$

3 0

3 years ago

Please help me find the area of this kite

iris [78.8K]

Answer:

The area of the kite is $56\ cm^{2}$

Step-by-step explanation:

we know that

The area of the kite is equal to

$A=\frac{1}{2}(D1*D2)$

where

D1 and D2 are the diagonals of the kite

we have

$D1=4+4=8\ cm$

$D2=10+4=14\ cm$

Find the area

$A=\frac{1}{2}(8*14)=56\ cm^{2}$

8 0

4 years ago