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ohaa [14]
4 years ago
10

If a person drives his car in the speed 50 miles per hour, how far can he cover the distance in 2.5 hours ?

Mathematics
2 answers:
Lady bird [3.3K]4 years ago
6 0

Answer:

125miles

Step-by-step explanation

distance=speed *time

d=50*2.5

d=125m

ad-work [718]4 years ago
4 0

Answer:

Hey there!

50 miles = 1 hour

x miles = 2.5 hours

50/1= x/2.5

x=2.5x50

x=125

The car can go 125 miles.

Hope this helps :)

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Well 3.4 goes into the house and 12.92 is outside of it. 3.4 is a smaller number so you'd add zeros to get the 12.92 into 3.4. As you add zeros you'd take the decimals out and move them to the right two times. But u actually move the decimal first than adding zeros. Step 1: Take out the decimals. Step 2: Add the zeros. Step 3: Hope this helped.
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Answer:

Step-by-step explanation:

3x²-17x=-10

3x²-17x+10=0

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3 years ago
Log 9-log 4÷log 3-log 2​
Minchanka [31]

Step-by-step explanation:

whoever created the original question and then probably the people copying it need to focus on writing these things correctly.

I assume this means

log(9) - log(4) ÷ log(3) - log(2)

or is anything combined in brackets ? like it could be e.g. log(4 ÷ log(3)). just as example.

and I guess we mean logarithm to the base of 10, right ?

anyway, if my assumptions are correct, then we only need to follow the regular priorities of mathematical operations :

1. brackets

2. exponents

3. multiplications and divisions

4. additions and subtractions

so, we need to start with the division in the middle, and then do the subtractions.

log(4) ÷ log(3) = 1.261859507...

log(9) - 1.261859507... = -0.307616998...

-0.307616998... - log(2) = -0.608646993...

or was the original question

(log(9) - log(4)) ÷ (log(3) - log(2))

?

that would be way more interesting.

we use the rules of logarithm :

e.g.

log(a×b) = log(a) + log(b)

log(a/b) = log(a) - log(b)

so, we have then

log(9/4) ÷ log(3/2)

and that is equal to

log(3/2 × 3/2) ÷ log(3/2)

(log(3/2) + log(3/2)) ÷ log(3/2) = 1 + 1 = 2

if that is the case, you really, REALLY need to pay more attention to brackets and other symbols in problem definitions.

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kramer

Answer:

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