Answer:
y=-4/13x-28/13
Step-by-step explanation:
m=y2-y1/x2-x1
m=-4-0/6-(-7)
m=-4-0/6+7
m=-4/13
y-y1=m(x-x1)
y-0=-4/13(x-(-7))
y-0=-4/13x-28/13
y=-4/13x-28/13
Answer:
Step-by-step explanation:
Let 
. We have that 
if and only if we can find scalars 
such that 
. This can be translated to the following equations:
1. 
2.
3. 
Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for 
and check if the third equationd is fulfilled.
Case (2,6,6)
Using equations 1 and 2 we get
whose unique solutions are 
, but note that for this values, the third equation doesn't hold (3+2 = 5 
6). So this vector is not in the generated space of u and v.
Case (-9,-2,5)
Using equations 1 and 2 we get
whose unique solutions are 
. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.
Here is the set up:
Let m = mass of the block
m = (30•40•50)/(2.8)
Use your calculator to calculate the left side for m.
7 days I think sorry if I’m wrong
