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Ostrovityanka [42]
4 years ago
14

I have another question 8x−8≤−72. please help

Mathematics
2 answers:
AnnyKZ [126]4 years ago
8 0
First move the -8 on the left to the right. this makes the inequality become 8x≤-64. Then you want to isolate the x by dividing 8x by 8, and make sure to do the same to -64. This makes it become x<span>≤-8, which is your final answer! Hope this helped :)</span>
melomori [17]4 years ago
6 0
We start off with this inequality:
8x - 8 <_ -72

To solve for x, we need to get 8x alone and then simplify.

8x - 8 <_ -72
Add 8 to both sides to get 8x alone.

-8 + 8 = 0
-72 + 8 = -64 (adding a negative to a positive is the equivalent to subtracting from a positive)

Our inequality now is:
8x <_ -64

8 is being multiplied by x, so we need to perform the opposite order of equations.
The opposite of multiplication is division.
Divide 8x by 8 and divide -64 by 8.
8x / 8 = x
-64 / 8 = -8 (Dividing a negative by a positive gives us a negative)

Your new and final inequality is:
x <_ -8

I hope this helps!
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