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Answer: 
Step-by-step explanation:
General equation of ellipse :
Given: Vertices of ellipse : (± 9,0)
Since the vertices are of the form (± a, 0).
i.e. a=9
Thus, the major axis is along x-axis.
Also, foci of the ellipse = (±5,0)
Since, foci is of the form (± c,0), i.e. c=5
Since

Equation of ellipse :

Hence, the required equation : 
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(-5, 12). Cosecant is the reciprocal of sine. Since csc theta =13/12, sin theta=12/13. We can narrow down to two angles, one in first quadrant and one in second quadrant. We are also given sec theta=-13/5, so cos theta=-5/13. Thus the angle is in the second quadrant. tan theta=1/cot theta=-12/5, so point (-5, 12) is on the ray.