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marta [7]
4 years ago
6

URGENT HELP NEEDED! Can someone PLEASE HELP. GEOMETRY...what is the equation of a line that is perpendicular to y=4x+5 and passe

s through the point (8 3) .
Mathematics
1 answer:
DiKsa [7]4 years ago
4 0
Hello,

Perpendicular sloop m is : 4*m=-1==>m=-1/4

Equation 's line is y-3=-1/4(x-8) or y=-x/4+5
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Lesson 13.3 Checkpoint
Arte-miy333 [17]

Answer:

a. LK = 4√3, JL= 4√6

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Step-by-step explanation:

a. LK =4√3,

LK=KJ= 4√3

sin(45°) = opposite/hypotenuse

hypotenuse (JL)= opposite/sin 45° = 4√3/√2/2 = 8√3/√2 = 8√3√2/2 = 4√6

b.

cos 30° = adjacent/hypotenuse = QR/PQ = 15/PQ

cos 30° = 15/PQ

PQ = 15/cos 30° = 15/√3/2)= 30/√3 = 30√3/3 = 10√3

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√3/3 = RP/QR

√3/3 = RP/15

RP = √3*15/3 = 5√3

3 0
3 years ago
57.036 in word form and in expanded form.
scoray [572]
Here is the answer: 

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Answer:

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I put the answer in an atachement

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