6. Find mZ1. (1 point

Mathematics

1 answer:

zhenek [66]4 years ago

8 0

First you have to find the angle that’s missing:

60+63+x=180
123+x=180
x=57

Now to find the missing exterior angle you do this:

x+57=180
x=123

Angle 1 would be 123 degrees.

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Find the surface area of the triangular prism. 15.6 cm 10 cm 11 cm 12 cm

dimulka [17.4K]

Answer:

533.6cm²

Step-by-step explanation:

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Area of each triangular base:

$\frac{1}{2}(12)(10)=60$

Area of the rectangular faces:

$12\times 11 =132$

$15.6\times 11=171.6$

$10\times 11=110$

Add to find the surface area:

$60+60+132+171.6+110=533.6$

Thus, the surface area of the triangular prism is = 533.6 yd²

Hope this helps you!

Hugs from,

Josh

6 0

3 years ago

Read 2 more answers

In ΔABC, AC = BC, CD ⊥ AB with D ∈ AB , AB = 4 in, and CD = sqrt3 in. Find AC.

amid [387]

Check the picture below.

segments AC and BC are equal, that means that ABC is an isosceles triangle, with twin sides. Now the twin sides make twin angles on the opposite side, namely the angles at A and B are twins.

if the angles at A and B are twins, and CD is ⟂ to AB, there's only one possibility that can happen, and is if CD is an angle bisector at C.

an angle bisector like CD with twin angles on each side, will cut AB in two equal halves, therefore, if AB = 4, then AD = 2 and DB = 2.