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SpyIntel [72]
4 years ago
13

6. Find mZ1. (1 point

Mathematics
1 answer:
zhenek [66]4 years ago
8 0
First you have to find the angle that’s missing:

60+63+x=180
123+x=180
x=57

Now to find the missing exterior angle you do this:

x+57=180
x=123

Angle 1 would be 123 degrees.
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What is 2/7 ÷ 4/21 fully reduced
NikAS [45]
When dividing fractions, you flip the second fraction and multiply

\dfrac{2}{7} \div \dfrac{4}{21}~becomes~\dfrac{2}{7}*\dfrac{21}{4}

Next, we multiply:

\dfrac{2}{7}*\dfrac{21}{4}=\dfrac{42}{28} = \dfrac{21}{14}= 1 \dfrac{1}{2} 

8 0
3 years ago
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Find x .<br><br> Select one:<br> a. 3/4 <br> b. 1/2 <br> c. 2 <br> d. 4
sashaice [31]

we are given

BE=x

ED=x+10

AE=x+1

EC=x+3

we can see that two chords AC and BD are intersecting inside the circle

so, we can use property

AE*EC=BE*ED

now, we can plug values

(x+1)*(x+3)=(x)*(x+10)

now, we can multiply them

x^2+4x+3=x^2+10x

now, we can move all terms on left side

x^2+4x+3-x^2-10x=0

3-6x=0

x=\frac{1}{2}...............Answer

6 0
3 years ago
Someone answer and do t try to take my points please. What do the Greeks and Romans have in common (similarities) in terms of th
stellarik [79]

Answer:

they are both polytheistic religions.

4 0
3 years ago
A gentleman earning $10 per hour gets a 20% raise. With her raise, how much will he earn after working 40 hours?
abruzzese [7]
I think it would 480$ if I’m correct
3 0
3 years ago
EASY TRIG - 15 POINTS
poizon [28]

Answer: The answers are (a) 40 cm and (b) \sin^{-1}\dfrac{23}{62}.


Step-by-step explanation: The calculations are as follows:

(a) See the figure (a). As given in the question, A circle with centre 'O' circumscribes a triangle ABC with BC = 20 cm and ∠BAC = 30°. We need to find the diameter DC of the circle.

Let us draw BD. Now, ∠BAC and ∠BDC are angles on the same arc BC, so we have

∠BAC = ∠BDC = 30°.

Also, ∠CBD = 90°, since it stands on the diameter DC. So, ΔBCD will be a right angled triangle.

We can write

\sin \angle BDC=\dfrac{BC}{DC}\\\\\\ \Rightarrow \sin 30^\circ=\dfrac{20}{DC}\\\\\\\Rightarrow \dfrac{1}{2}=\dfrac{20}{DC}\\\\\\\Rightarrow DC=40.

Thus, the diameter of the circle = 40 cm.


(b) See the figure (b).

As given in the question, A circle with centre 'O'' circumscribes a triangle DEF with EF = 4.6 inches and diameter GF = 12.4 in.. We need to find the angle EDF.

Let us draw GE. Now, ∠EGF and ∠EDF are angles on the same arc EF, so we have

∠EGF = ∠EDF = ?

Also, ∠GEF = 90°, since it stands on the diameter GF. So, ΔGEF will be a right angled triangle.

We can write

\sin \angle EGF=\dfrac{EF}{GF}\\\\\\ \Rightarrow \sin \angle EGF=\dfrac{4.6}{12.4}\\\\\\\Rightarrow \sin \angle EGF=\dfrac{23}{62}\\\\\\\Rightarrow \angle EGF=\sin^{-1}\dfrac{23}{62}.

Thus,

\angle EDF=\angle EGF=\sin^{-1}\dfrac{23}{62}.

4 0
3 years ago
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