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2 years ago

ANSWER ASAP I NEED THIS NOW!!!! please and thank you

Mathematics

2 answers:

galben [10]2 years ago

8 0

Answer:

1. 920.0, 1830/2, 9.1 x 10^2, 918%

2. B

VikaD [51]2 years ago

3 0

Answer:

Good luck honey.

Step-by-step explanation:

Everyone on this website don't like to help other people who need answers quick. I would help you but the pictures are blocked because i have a shcool computer. type the question out and will help. maybe someone will eventually help me.

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Use the law of wines to find the value of y. Round to the nearest Tenth

Eva8 [605]

Answer:

y ≈ 2.5

Step-by-step explanation:

Using the Sine rule in Δ XYZ

$\frac{sinZ}{XY}$ = $\frac{sinY}{XZ}$ , substitute values

$\frac{sin50}{2}$ = $\frac{sin75}{y}$ ( cross- multiply )

y sin50° = 2 sin75° ( divide both sides by sin50° )

y = $\frac{2sin75}{sin50}$ ≈ 2.5 ( to the nearest tenth )

4 0

2 years ago

2.5 hours is equal to 2 hours and 30 minutes <br> True or false<br>

Feliz [49]

Answer:

True because 1/2 an hour is 30 minutes.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

I will give brainliest please hurry

Eduardwww [97]

Answer:

Step-by-step explanation:

300, since the line inside the box is on 300

Hope that helps!

6 0

2 years ago

Read 2 more answers

Find the value of x in the triangle shown below.

DIA [1.3K]

Answer:

x=8

Step-by-step explanation:

We can use the Pythagorean theorem to solve

a^2+b^2 = c^2 where a and b are the legs and c is the hypotenuse

6^2 + x^2 = 10^2

36 + x^2 = 100

Subtract 36 from each side

36-36 +x^2 = 100-36

x^2 = 64

Take the square root of each side

sqrt(x^2) = sqrt(64)

x = 8

7 0

2 years ago

Read 2 more answers

A college professor never finishes his lecture before the end of the hour and always finishes his lectures within 2 min after th

Citrus2011 [14]

Answer:

Value of k is $\displaystyle\frac{3}{8}$

Step-by-step explanation:

We are given the following information in the question:

$f(x) = kx^2, 0\leq x \leq 2\\~~~~~~~= 0, \text{ otherwise}$

where x is the time elapses between the end of the hour and the end of the lecture.

We have to find the values of k.

Since, f(x) is the pdf, then,

$\displaystyle\int^\infty_{-\infty} f(x) = 1\\\\\displaystyle\int^2_{0} f(x) = 1\\\\\displaystyle\int^2_{0} kx^2 = 1\\\\k\bigg[\frac{x^3}{3}\bigg]^2_0 = 1\\\\k\times \frac{8}{3} = 1\\\\k = \frac{3}{8}$

Hence, value of k is $\displaystyle\frac{3}{8}$

4 0

2 years ago