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Rina8888 [55]
4 years ago
8

Simplify completely quantity 5 x squared plus 9 x minus 2 over quantity x squared plus 12 x plus 20 times quantity x squared plu

s 17 x plus 70 over.
Mathematics
1 answer:
Mashutka [201]4 years ago
6 0
(x+2)(5x-1) (x+10)(x+7)
(x+10)(x+2) 3(5x-1)

Cancel like factors and you're left with. (x+7)/3
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Select the correct answer.
Licemer1 [7]

Answer:

C

Step-by-step explanation:

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5 0
3 years ago
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I need help ASAP ! Please!!!!!!
DENIUS [597]

Answer: Its the first choice

Step-by-step explanation:

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3 years ago
On paper, draw and label point P. Draw and label point Q. Draw a line between the two points using a straight edge. What is the
Veseljchak [2.6K]
Just draw what the instruction says and you will get the answer
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3 years ago
What differentiable functions have an arc length on the interval [a, b] given by the following integrals? Note that the answers
Dafna1 [17]

Answer:

a) \pm 8\frac{x^{5}}{5}+C

b) \pm 4 sin(2x) + C

Step-by-step explanation:

Given integrals are:

a) \int\limits^a_b {\sqrt{{1+64x^{8}} } \, dx ---(1)

b) \int\limits^a_b {\sqrt{1+64cos^{2}(2x)} } \, dx---- (2)

Standard form

                L= \int\limits^a_b {\sqrt{1+(f'(x))^{2}} } \, dx

<h3>Part A</h3>

compare (1) with standard form

[f'(x)]^{2} = 64x^{8}\\f'(x)=\pm 8x^{4}\\f(x)= \pm8\frac{x^{5}}{5}+C

<h3>Part B</h3>

Compare (2) with standard form

[f'(x)]^{2}=64cos^{2}(2x)\\f'(x)= \pm 8cos(2x)\\f(x)=\pm 8\frac{sin(2x)}{2}+C\\f(x)= \pm 4sin(2x)+C

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3 years ago
What are the coordinates of the image of vertex G after a reflection across the line y=x ?
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Answer:

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