1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).
2. Use formula 
to find the distance from point 
to the line Ax+By+C=0.
The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:
.
3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.
Answer: 
.
Answer:
13
Step-by-step explanation:
You are given the function
To find the value of the function f(x) at point x=a, you have to substitute a instead of x into the function expression.
In your case, you have to evaluate f(x) when x=10. Substitute 10 instead of x into the function expression:
Answer:
40
Step-by-step explanation:
C=(5/9)(104-32)
C=(5/9)(72)
C=40
Answer:
1/9th.
Step-by-step explanation:
Because the area is measured in units squared, then you have to square 1/3 which is 19th.
Answer:
Collect Like terms...Then Take the LCM
1/4x -1/3x +3 - 2
-1/12x + 1
Or
1 - 1/12x .
Option D.
