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3 years ago

9

What value should go in the empty boxes to complete the calculation for finding the product of 0.61 × 0.45? Both numbers are the

same; however, only input the number one time in your answer

1 answer:

nalin [4]3 years ago

7 0

its 0.106 because I said so

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A system of equations and its solution are given below.

Fittoniya [83]

Answer: Option <span>C. To get system B, the second equation in system A was replaced by the sum of that equation and the first equation multiplied by -3. The solution to system B will be the same as the solution to system A.

First equation of system A multiplied by -3:
(-3)(x+6y=5)
(-3)(x)+(-3)(6)=(-3)(5)
-3x-18=-15

Sum of the second equation of system A and the first equation multiplied by -3:
(-3x-18)+(3x-7y)=(-15)+(-35)
-3x-18+3x-7y=-15-35
-25y=-50

System B
x+6y=5
-25y=-50 </span>

4 0

3 years ago

Read 2 more answers

A bank with a branch located in a commercial district of a city has the business objective of developing an improved process for

tatiyna

Answer:

(a) The test statistic value is -4.123.

(b) The critical values of <em>t</em> are ± 2.052.

Step-by-step explanation:

In this case we need to determine whether there is evidence of a difference in the mean waiting time between the two branches.

The hypothesis can be defined as follows:

<em>H₀</em>: There is no difference in the mean waiting time between the two branches, i.e. <em>μ</em>₁ - <em>μ</em>₂ = 0.

<em>Hₐ</em>: There is a difference in the mean waiting time between the two branches, i.e. <em>μ</em>₁ - <em>μ</em>₂ ≠ 0.

The data collected for 15 randomly selected customers, from bank 1 is:

S = {4.21, 5.55, 3.02, 5.13, 4.77, 2.34, 3.54, 3.20, 4.50, 6.10, 0.38, 5.12, 6.46, 6.19, 3.79}

Compute the sample mean and sample standard deviation for Bank 1 as follows:

$\bar x_{1}=\frac{1}{n_{1}}\sum X_{1}=\frac{1}{15}[4.21+5.55+...+3.79]=4.29$

$s_{1}=\sqrt{\frac{1}{n_{1}-1}\sum (X_{1}-\bar x_{1})^{2}}\\=\sqrt{\frac{1}{15-1}[(4.21-4.29)^{2}+(5.55-4.29)^{2}+...+(3.79-4.29)^{2}]}\\=1.64$

The data collected for 15 randomly selected customers, from bank 2 is:

S = {9.66 , 5.90 , 8.02 , 5.79 , 8.73 , 3.82 , 8.01 , 8.35 , 10.49 , 6.68 , 5.64 , 4.08 , 6.17 , 9.91 , 5.47}

Compute the sample mean and sample standard deviation for Bank 2 as follows:

$\bar x_{2}=\frac{1}{n_{2}}\sum X_{2}=\frac{1}{15}[9.66+5.90+...+5.47]=7.11$

$s_{2}=\sqrt{\frac{1}{n_{2}-1}\sum (X_{2}-\bar x_{2})^{2}}\\=\sqrt{\frac{1}{15-1}[(9.66-7.11)^{2}+(5.90-7.11)^{2}+...+(5.47-7.11)^{2}]}\\=2.08$

(a)

It is provided that the population variances are not equal. And since the value of population variances are not provided we will use a <em>t</em>-test for two means.

Compute the test statistic value as follows:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}}}$

$=\frac{4.29-7.11}{\sqrt{\frac{1.64^{2}}{15}+\frac{2.08^{2}}{15}}}$

$=-4.123$

Thus, the test statistic value is -4.123.

(b)

The degrees of freedom of the test is:

$m=\frac{[\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}]^{2}}{\frac{(\frac{s_{1}^{2}}{n_{1}})^{2}}{n_{1}-1}+\frac{(\frac{s_{2}^{2}}{n_{2}})^{2}}{n_{2}-1}}$

$=\frac{[\frac{1.64^{2}}{15}+\frac{2.08^{2}}{15}]^{2}}{\frac{(\frac{1.64^{2}}{15})^{2}}{15-1}+\frac{(\frac{2.08^{2}}{15})^{2}}{15-1}}$

$=26.55\\\approx 27$

Compute the critical value for <em>α</em> = 0.05 as follows:

$t_{\alpha/2, m}=t_{0.025, 27}=\pm2.052$

*Use a <em>t</em>-table for the values.

Thus, the critical values of <em>t</em> are ± 2.052.

3 0

3 years ago

Please Help. NO LINKS OR DOWNLOADS OR YOU WILL BE REPORTED.

Aliun [14]

Did you attach a picture to this, It could be my internet but it’s not showing up on my screen

3 0

3 years ago

What’s the answer guys?

never [62]

Answer:

the first one is the answer, with maybe the third if you can choose multiple.

Step-by-step explanation:

Let's go throught hese one at a time. First though it is important to note that the poitns look like they are going upward. So we want a relationship that it makes sense as one increases so does the other.

the amount of money made made compared to the amount of items sold

So, pretending we run a store. Does it make sense that if we make more money more items were sold? I would say so.

the amoutn of ink left in a pen compared to the time using it

Doe sit make sense that as the amount of ink increases the time using it increases? i would say no, because ink usually decreases the more it is used.

the amount of money in your account compared to the number of stores that you shop at

Does it make sense that if you have more money in your account you shop at more stores? I think so, though the first one still makes the most sense if you can only pick one. Since it doesn't seem directly to imply that, I would say it makes more sense that you just but more in general, not necessarily from more stores.

the number of goals scored in a soccer match compared to the number of red cards given

does it make sense that more goals would also have more red cards? i don't think so, though I don't know soccer that much. it doesn't seem like goals mean there should be any more red cards.

So in total it seems like the first one is the answer, with maybe the third if you can choose multiple.

4 0

3 years ago

Jasmine found a wooden jewelry box shaped like a right rectangular prism. What

Eduardwww [97]

Answer:

8cm

Step-by-step explanation:

8 because $\sqrt[3]{8}$ is 2

7 0

3 years ago

Read 2 more answers