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3 years ago

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4. If Mahamat has 36 coins totaling $3.00, and the coins are all nickels and quarters, how many of each coin does he have?

1 answer:

MakcuM [25]3 years ago

6 0

The answer is 30 i believe :) ♡

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Two different factories both produce a certain automobile part. The probability that a component from the first factory is defec

Ulleksa [173]

Answer:

a. 55.56%

b. 44.44%

c. 3.33%

d. 33.33%

Step-by-step explanation:

total supply = 180

a. In the first factory the total number obtained = 100

probability that the chosen part is from the first

= 100/180

= 0.5556

= 55.56%

b. In the second factory total = 80

probability that the chosen part is from the second

= 80/180

= 0.4444

= 44.44%

c. probability that part chosen at random from 180 is defective

= 2% * 0.5556 + 5% * 0.4444

= 0.02*0.5556 + 0.05*0.4444

= 0.011112 + 0.0222

= 0.03331

= 3.33%

d. probability it came rom the first factory if it is defective

$\frac{0.02*0.5556}{0.02*0.5556+0.05*0.4444}$

= $\frac{0.011112}{0.011112+0.0222}$

= $\frac{0.011112}{0.033312}$

= 0.33357

= 33.33%

5 0

3 years ago

What is the equation of the line that passes through the point

snow_lady [41]

Answer:

$3x-2y=2$

Step-by-step explanation:

The equation of line having slope $\frac{3}{2}$ and passing through $(-4,-7)$ .

$The\ equation\ of\ line\ is\ given\ by\ y=mx+c\ where\ m\ is\ the\ slope\ of\ line.\\\\Here\ m=\frac{3}{2}\\\\Equation\ y=\frac{3}{2}x+c\\\\Line\ passes\ through\ (-4,-7),\ it\ will\ satisfy\ the\ equation\ of\ line.\\\\-7=\frac{3}{2}\times (-4)+c\\\\-7=-6+c\\\\c=-7+6\\\\c=-1\\\\y=\frac{3}{2}x-1\\\\2y=3x-2\\\\3x-2y=2$

8 0

4 years ago

Jovan has $14,000 in a savings account. The savings collect interest at a 7% annual rate that compounds every year. How much mon

wel

Answer:

sorry 98928

Step-by-step explanation:

8 0

3 years ago

The owner of an automobile insures it against damage by purchasing an insurance policy with a deductible of 250. In the event th

choli [55]

Answer:

Step-by-step explanation:

From the given information:

The uniform distribution can be represented by:

$f_x(x) = \dfrac{1}{1500} ; o \le x \le \ 1500$

The function of the insurance is:

$I(x) = \left \{ {{0, \ \ \ x \le 250} \atop {x -20 , \ \ \ \ \ 250 \le x \le 1500}} \right.$

Hence, the variance of the insurance can also be an account forum.

$Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2$

here;

$E[I(x)] = \int f_x(x) I (x) \ sx$

$E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx$

$= \dfrac{1}{1500 } \dfrac{(x - 250)^2}{2} \Big |^{1500}_{250}$

$\dfrac{5}{12} \times 1250$

Similarly;

$E[I^2(x)] = \int f_x(x) I^2 (x) \ sx$

$E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx$

$= \dfrac{1}{1500 } \dfrac{(x - 250)^3}{3} \Big |^{1500}_{250}$

$\dfrac{5}{18} \times 1250^2$

∴

$Var {I(x)} = 1250^2 \Big [ \dfrac{5}{18} - \dfrac{25}{144}]$

Finally, the standard deviation of the insurance payment is:

$= \sqrt{Var(I(x))}$

$= 1250 \sqrt{\dfrac{5}{48}}$

≅ 404

4 0

3 years ago

B. The sum of three numbers is 51. The second number is three more than the first number, and the third number is

Svetach [21]

Answer:

12, 15, 24

Step-by-step explanation:

Let 1st # = x

Let 2nd # = x+3

Let 3rd # = 2x

Your equation is: x + (x+3) + 2x = 51

Add up all the x: x + x +3 +2x =51

Subtract 3 from both sides: 4x + 3 - 3 = 51 - 3

Divide 4 from both sides: 4x / 4 = 48 / 4

Your 1st number is x = 12

For the 2nd # it is 3 more than x so 12 + 3 = 15

For the 3rd # it is 2 times x so 2(12) = 24

Check your answers by adding up the numbers you solved: 12 + 15 +24 = 51

Does it equal to 51 as stated in the question? Yes, answers check out.

7 0

3 years ago