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Klio2033 [76]
3 years ago
14

30 POINTS !!!!!!!!!!! When dealing with an equation containing two variables, we can put the graph of the equation on the coordi

nate plane because the number of variables is equal to the number of dimensions that are needed to properly graph the solution. Each axis on a graph represents one variable in the equation being graphed. What would you use to graph the solution to an equation with one variable? What would you use to graph the solution to an equation with three variables? Could you graph an equation containing more than four variables? Explain. If you were given the graph of an equation with two variables on a coordinate plane, what would happen to the graph if all the y-values were increased by 1? What would happen to the graph if all the x-values were increased by 1? What would happen to the graph if all the y-values were multiplied by 2 or by 1/2? Explain

Mathematics
1 answer:
quester [9]3 years ago
3 0
Lol its actually half of what u put into it but its all good.
I hope this will help u with ur answer, and next time copy and paste the answer into google, its easier to do that then waste 30 good points.
anyways don't forget to take a look at my profile to repay the favor.

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The new iPhone 3.14 is being sold at the UT Math Department. The original price is $1200 (day 0), but they are going to decrease
Marat540 [252]

\bf \qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{accumulated amount}\dotfill&50.14\\ P=\textit{initial amount}\dotfill &1200\\ r=rate\to r\%\to \frac{r}{100}\dotfill\\ t=\textit{elapsed time}\dotfill &16\\ \end{cases}


\bf 50.14=1200(1-r)^{16}\implies \cfrac{50.14}{1200}=(1-r)^{16}\implies \sqrt[16]{\cfrac{50.14}{1200}}=1-r \\\\\\ r=1-\sqrt[16]{\cfrac{50.14}{1200}}\implies r\approx 0.18\implies \stackrel{\textit{converting to percent}}{r\approx 0.18\cdot 100}\implies r\approx \stackrel{\%}{18}\quad \leftarrow x

3 0
3 years ago
What is the equation of the parabola with a directrix at y = 4 and focus (0, -4).
Svet_ta [14]
Given that the directrix is at y = 4 and the focus is at (0, -4), then the vertex is at (h, k) = (0, 0).
p is the distance between the vertex and the focus and between the vertex and the directrix = 4 and since the focus is below the directrix, p is negative, i.e. p = -4
Equation of a parabola is given by (x - h)^2 = 4p(y - k)
Therefore, the required equation is (x - 0)^2 = 4(-4)(y - 0)
x^2 = -16y
y = -1/16 x^2
3 0
3 years ago
In how many different ways can 10 be written as a sum of odd numbers
kakasveta [241]
5+5=10
3+1+1=10
1+1+1+1+1=10

Hope this Helps!
7 0
3 years ago
Point P is located at (–3, –2). P is reflected across the x-axis to create P'. What quadrant is P' in?
Eva8 [605]
Look at the axis graph. If both of the coordinates are negative, it would be in quadrant lll. If you go over to the x-axis, you would be in quadrant lV, or 4.

(-2,-3) -> (2,-3)

You change the x-factor's sign. 

I hope this helps!
~kaikers

4 0
3 years ago
Wxyz is a rectangle, what is zx
Alika [10]
ZX is a diagonal line from corner to corner.
6 0
3 years ago
Read 2 more answers
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