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3 years ago

Does anybody possibly know how to help me with this?

Mathematics

2 answers:

solong [7]3 years ago

7 0

The answer should be .a.Multiply the rate by the time.

IrinaVladis [17]3 years ago

5 0

A would be the answer.

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How do I find the perimeter of this ?

gavmur [86]

Answer:

26 is the perimeter

Step-by-step explanation:

you add all of the side numbers just like this:

9+5+12= 26 :)

Hope this helped :D

3 0

3 years ago

Can anyone help it would mean alot im struggling right now

Setler79 [48]

Answer:

what do you need? ^-^ I can help you

6 0

2 years ago

Which situation could be solved using the equation -4+4=0

navik [9.2K]

we are supposed to explain

Which situation could be solved using the equation $-4+4=0$

As we can see in the given equation , one number is -4 and the other number is 4

When we add two number of same value but opposite in sign we get zero.

This equivalent to the real life situation of paying a post paid bills.

Suppose you are using a post paid service , and the bills gets generated at the end of the month.

Suppose the bills amount is $x.

Once you pay that bills , then total outstanding again becomes $0.

Because $-x+x=0$

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

2 years ago

Sin(x+20) - cos (2X+10)

Vladimir [108]

Answer:

X=20

Step-by-step explanation:

Sin(x+20)=cos(2x+10)

Sin(x+20)=sin(90-(2x+10)

X+20=90-2x-10

3x=60

X=20

8 0

3 years ago