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3 years ago

Please help me with this

Mathematics

1 answer:

jeyben [28]3 years ago

5 0

Answer:

y=1x

Step-by-step explanation:

if you divide y over x, you get 1

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Eight less than the product of 2 and a number x ?

mars1129 [50]

Eight less than the product of 2 and a number x is: 2x-8

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3 years ago

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How many solutions does the following have. Y=3x-2 and 2x+5y=7

bezimeni [28]

One, the intersection point is (1,1)

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3 years ago

What is the probability

gulaghasi [49]

Answer: Last Option

$P=0.4125$

Step-by-step explanation:

In this case we have a uniform probability. In the graph the horizontal axis represents the possible values of the variable x and the vertical axis represents the probability P(x).

To calculate the probability that x is between 4.71 and 7.4 we calculate the area under the curve.

The horizontal length between 4.71 and 7.4 is:

$7.4-4.1 = 3.3$ .

Then notice that the vertical length in this interval is 0.125.

Then the area of a rectangle is:

$A = lw$

Where l is the length and w is the width.

In this case we have to:

$l = 3.3$

$w = 0.125$

$P = A = 3.3 * 0.125$

$P=0.4125$

3 0

3 years ago

Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form

Alex787 [66]

Answer:

$y=-\frac{2}{5}x-\frac{1}{5}$

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

m is the slope

b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

$m = -\frac{2}{5}$

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

$y=-\frac{2}{5}x + b$

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-3,1). When x of the line is -3, y of the line must be 1.
(2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: $y=-\frac{2}{5}x + b$ . $b$ is what we want, the - $-\frac{2}{5}$ is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

(-3,1). y = mx + b or $1=-\frac{2}{5} * -3 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(-3)$ . $b = -\frac{1}{5}$ .
(2,-1). y = mx + b or $-1=-\frac{2}{5} * 2 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(2)$ . $b = -\frac{1}{5}$ .