The 4:00 time because later that afternoon would be later in the day
Answer: The energy required to vaporize 12.5 g of liquid water is 28.2 kJ
Explanation:
Latent heat of vaporization is the amount of heat required to convert 1 gram of liquid into its vapor state without change in its temperature.
Given : The enthalpy of vaporization of water is 40.65 kJ/mol.
n = number of moles =
Thus 1 mole of water requires heat = 40.65 kJ
0.694 moles of water requires heat =
Thus the energy required to vaporize 12.5 g of liquid water is 28.2 kJ
Can you post the question
The correct option is C.
For an element to be unreactive and stable, it must have eight electrons in its outermost shell. Sodium has an atomic number of 11 and thus have only one electron in its outermost shell. This makes sodium very reactive and it is always very willing to react with suitable elements in order to become stable.
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Answer:</h3>
The mole fraction of carbon dioxide is 0.0559
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Explanation:</h3>
- Mole fraction of a gas in a mixture of gases its given by dividing the number of moles of the gas by the total number of moles of the mixture.
In this case, we are given a mixture of N₂, CO₂ and He
To find the mole fraction of CO₂, first we need to calculate the total number of moles in the mixture.
Individual number of moles for each gas are;
Moles = mass ÷ Molar mass
Therefore;
Nitrogen gas (N₂)
Mass =18.0 g
Molar mass = 28.02 g/mol
= 0.642 moles N₂
Helium gas (He)
Mass = 50.5 g
Molar mass = 4.0 g/mol
= 12.625 moles He
Carbon dioxide (CO₂)
Mass = 34.6 g
Molar mass = 44.01 g/mol
= 0.786 moles CO₂
Therefore;
The total number of moles in the mixture;
= 0.642 moles + 12.625 moles + 0.786 moles
= 14.053 moles
Thus;
The mole fraction of CO₂= Moles of CO₂ ÷ Total number of moles
= 0.786 moles ÷ 14.053 moles
= 0.0559
Hence the mole fraction of carbon dioxide is 0.0559