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4 years ago

Solve each equation of 23=7x

Mathematics

1 answer:

solniwko [45]4 years ago

8 0

23=7x
Divide both sides by 7
23/7=x
That is the only answer to this equation

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Determine whether each quadrilateral is a parallelogram. Write yes or no. If yes, give a reason for your answer.

emmasim [6.3K]

Answer:

yes

Step-by-step explanation:

All of the opposite sides are parallel to each other.

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3 years ago

Find the volume of this cylinder. Use 3 for .

vivado [14]

Answer:

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is the answer

4 0

3 years ago

What is the recipricol of 1000

Mrac [35]

The reciprocal of a number x is 1/x.

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7 0

3 years ago

Read 2 more answers

You are curious about the average number of yards Matthew Stafford throws for each game for the Detroit Lions. You randomly sele

Damm [24]

Answer:

The margin of error for this estimate is of 14.79 yards per game.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

T interval

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 20 - 1 = 19

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.093

The margin of error is:

$M = T\frac{s}{\sqrt{n}}$

In which s is the standard deviation of the sample and n is the size of the sample.

You randomly select 20 games and see that the average yards per game is 273.7 with a standard deviation of 31.64 yards.

This means that $n = 20, s = 31.61$

What is the margin of error for this estimate?

$M = T\frac{s}{\sqrt{n}}$

$M = 2.093\frac{31.61}{\sqrt{20}}$

$M = 14.79$

The margin of error for this estimate is of 14.79 yards per game.

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B3x%7D%5E%7B2%7D%20%7D%7Bxy%7D%20%20%5Ctimes%20%20%5Cfrac%7B%20%7B4xy%7D%5E%

hjlf

$\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
\cfrac{3x^2}{xy}\cdot \cfrac{4xy^2}{\frac{1}{y}}\implies \cfrac{3x^2}{xy}\cdot \cfrac{4xy^2}{y^{-1}}\implies \cfrac{3x^2x^1y^2}{xy^1y^{-1}}\implies \cfrac{3x^{2+1}y^2}{xy^{1-1}}
\\\\\\
\cfrac{3x^3y^2}{xy^0}\implies \cfrac{3x^3y^2}{x^1}\implies 3x^3y^2x^{-1}\implies 3x^{3-1}y^2\implies 3x^2y^2$

6 0

3 years ago