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3 years ago

If A= (0,0) and B = (2,5) what is the appropriate length of AB

Mathematics

2 answers:

masya89 [10]3 years ago

6 0

Answer:

$\sqrt{29}$

Step-by-step explanation:

Use the distance formula. $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

Plug in the coordinates into the equation. $\sqrt{(2-0)^{2}+(5-0)^{2}}$

Solve the distance formula. $\sqrt{(2)^{2}+(5)^{2}}$ --> $\sqrt{4+25}$ --> $\sqrt{29}$

sp2606 [1]3 years ago

4 0

Answer:

Use the formula for the distance between two points: d = √((x2 – x1)2 + (y2 – y12))

Step-by-step explanation:

d = √((5 – 0)2 + (2 – 0)2

d = √(25 + 4) = √(29) ≈ 5.385

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dusya [7]

Equation of a line:
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m = gradient: The difference between two y points and two x points.
$m= \frac{\Delta y}{\Delta x}$

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$y=\textunderscore\textunderscore \ x + \textunderscore$
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To calculate m find two y coordinates -you have (12, 7) and (0, 1)- and subtract them. Then divide this by the subtracted values of the x coordinates -you have (12, 7) and (0, 1)- This gives:

$m= \frac{7-1}{12-0}$
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To calculate the c, you just see where the line crosses the y-axis. Because you have the point (0, 1), you know that when x=0, y=1. Because x=0 is on the y-axis, you can tell that the line passes through y=1. This makes your c = 1:

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3 years ago