Answer:
Part 22) The area is
and the perimeter is 
Part 24) The area is
and the perimeter is
Part 26) The area is equal to 
Step-by-step explanation:
Part 22) Find the perimeter and area
step 1
The area of a rectangle is equal to

we have


Remember that
When multiply exponents with the same base, adds the exponents and maintain the base
substitute in the formula


step 2
The perimeter of a rectangle is equal to

we have

substitute in the formula


Part 24) Find the perimeter and area
step 1
The area of triangle is equal to

where


Remember that
When multiply exponents with the same base, adds the exponents and maintain the base
substitute the given values


step 2
Find the perimeter
I will assume that is an equilateral triangle (has three equal length sides)
The perimeter of an equilateral triangle is

where

substitute


Part 26) Find the area
The area of a circle is equal to

where

Remember the property

substitute in the formula the given value


Answer:
Let the Dulcina's collection be 'x'
Let the Tremaine collection be 'x-39'
x + x - 39 =129
2x = 129 +39
2x = 168
x = 168/2
x = 84
Dulcina's collection = x = 84
Tremaine's collection = x - 39 = 84 - 39 = 45
Answer:
0.3
Step-by-step explanation:
Answer:
Um threre is no blanks or there is no question.
Step-by-step explanation:
The answer is
200%Why? --- A change from 12 to 36 represents a positive change (increase) of 200%
Use the formula found below on this webpage to find the percent change by replacing the given values:
Percent change = [(12 - 36) / 12] x 100 = 200 % (increase)
Where: 12 is the old value and 36 is the new value. In this case we have a positive change (increase) of 200 percent because the new value is greater than the old value.
Hope this helps. :)
~
Anonymous