Can you guys help me with this question

A quadrilateral has no pairs of parallel sides, what two shapes could it be?

marin [14]

Answer:

Kite

Step-by-step explanation:

Def of kite has no parallel sides

3 0

3 years ago

Read 2 more answers

1 + (2/3) - (-9/2) =

Bad White [126]

Answer..............

6 0

3 years ago

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1/4 + 5/12 i rlly need this

loris [4]

8/12 is the answer bc 1/4 can be converted to 3/12 and with a common denominator you can now add and you’ll get 8/12

4 0

3 years ago

Let e1= 1 0 and e2= 0 1 , y1= 4 5 , and y2= −2 7 , and let T: ℝ2→ℝ2 be a linear transformation that maps e1 into y1 and maps

Furkat [3]

Answer:

The image of $\left[\begin{array}{c}4&-4\end{array}\right]$ through T is $\left[\begin{array}{c}24&-8\end{array}\right]$

Step-by-step explanation:

We know that $T:$ $IR^{2}$ → $IR^{2}$ is a linear transformation that maps $e_{1}$ into $y_{1}$ ⇒

$T(e_{1})=y_{1}$

And also maps $e_{2}$ into $y_{2}$ ⇒

$T(e_{2})=y_{2}$

We need to find the image of the vector $\left[\begin{array}{c}4&-4\end{array}\right]$

We know that exists a matrix A from $IR^{2x2}$ (because of how T was defined) such that :

$T(x)=Ax$ for all x ∈ $IR^{2}$

We can find the matrix A by applying T to a base of the domain ( $IR^{2}$ ).

Notice that we have that data :

$B_{IR^{2}}=$ { $e_{1},e_{2}$ }

Being $B_{IR^{2}}$ the cannonic base of $IR^{2}$

The following step is to put the images from the vectors of the base into the columns of the new matrix A :

$T(\left[\begin{array}{c}1&0\end{array}\right])=\left[\begin{array}{c}4&5\end{array}\right]$ (Data of the problem)

$T(\left[\begin{array}{c}0&1\end{array}\right])=\left[\begin{array}{c}-2&7\end{array}\right]$ (Data of the problem)

Writing the matrix A :

$A=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]$

Now with the matrix A we can find the image of $\left[\begin{array}{c}4&-4\\\end{array}\right]$ such as :

$T(x)=Ax$ ⇒

$T(\left[\begin{array}{c}4&-4\end{array}\right])=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]\left[\begin{array}{c}4&-4\end{array}\right]=\left[\begin{array}{c}24&-8\end{array}\right]$

We found out that the image of $\left[\begin{array}{c}4&-4\end{array}\right]$ through T is the vector $\left[\begin{array}{c}24&-8\end{array}\right]$

3 0

3 years ago

Paul Colin and Brian are waiters. One night the restaurant earns tips totalling £77.40. They share the tips in the ratio 2:3:4.

MatroZZZ [7]

Given:

Total tip = £77.40

Paul, Colin and Brian share the tips in the ratio 2:3:4.

To find:

How much more does Brian get over Paul?

Solution:

Let the shares of Paul, Colin and Brian are 2x, 3x and 4x respectively.

$2x+3x+4x=77.40$

$9x=77.40$

$x=\dfrac{77.40}{9}$

$x=8.6$

Now, the different between Brian and Paul share is

$Difference=4x-2x$

$Difference=2x$

$Difference=2(8.6)$

$Difference=17.2$

Therefore, Brain get £17.2 much more over Paul.

4 0

3 years ago