Answer:
The coordinates of H' are (-2 , 0)
Step-by-step explanation:
* Lets explain how to solve the problem
- A vertical stretching is the stretching of the graph away from
the x-axis
- If k > 1, the graph of y = k•f(x) is the graph of f(x) vertically stretched
by multiplying each of its y-coordinates by k.
- A vertical compression is the squeezing of the graph toward
the x-axis.
- If 0 < k < 1 (a fraction), the graph of y = k•f(x) is f(x) vertically
compressed by multiplying each of its y-coordinates by k.
- In the problem
∵ Square EFGH stretches vertically by a factor of 2.5
∵ Its image is the rectangle E'F'G'H'
∵The square stretches with respect to the x-axis
∴ The y-coordinates of all the point of the square will multiply by
the factor of the stretching
∵ The factor of the stretching is 2.5
∵ The coordinates of point H are (-2 , 0)
∴ H' = (-2 , 0 × 2.5) = (-2 , 0)
∴ The coordinates of H' are (-2 , 0)
