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Hunter-Best [27]
3 years ago
9

Answer for 5 help me please !!!

Mathematics
2 answers:
77julia77 [94]3 years ago
5 0
156 sq ft by 13x12. I hope this really helps you!
rjkz [21]3 years ago
3 0
Surface area is 716.28
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HELLO PLEASE GIVE ME THE RIGHT ANSWER ASAP THANK YOU !
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\large\underline{\sf{Solution-}}

\textsf{Given expression;}\\

\rm{23 =  \frac{7}{9}(6x - 36) + 9 } \\

\rm{\longmapsto} \: 23 =  \frac{(42x - 256)}{9}  + 9 \\

\rm{\longmapsto} \: 23 =  \frac{(42x - 256 + 81)}{9}  \\

\rm{\longmapsto} \: 23 =  \frac{(42x - 175)}{9}  \\

\rm{\longmapsto} \:  \frac{23}{1}  =  \frac{(42x - 175)}{9}  \\

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\rm{\longmapsto}23(9) = 1(42x - 175) \\

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\rm{\longmapsto} \: 42x =  - 175 - 207 \\

\rm{\longmapsto} \: 42x =  - 379 \\

\rm \therefore \: x =  -  \frac{375}{42}  \\

\textsf{Hence, the value of x will be -375/42 respectively.}\\

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discrete random variable X has the following probability distribution: x 13 18 20 24 27 P ( x ) 0.22 0.25 0.20 0.17 0.16 Compute
tatuchka [14]

Answer:

(a) P(X = 18) = 0.25

(b) P(X > 18) = 0.53

(c) P(X ≤ 18) = 0.47

(d) Mean = 19.76

(e) Variance = 22.2824

(f) Standard deviation = 4.7204

Step-by-step explanation:

We are given that discrete random variable X has the following probability distribution:

            X                    P (x)             X * P(x)            X^{2}             X^{2} * P(x)

           13                    0.22              2.86              169              37.18

           18                    0.25              4.5                324               81

           20                   0.20               4                  400               80

           24                    0.17              4.08              576              97.92

           27                    0.16              4.32              729             116.64

(a) P ( X = 18) = P(x) corresponding to X = 18 i.e. 0.25

     Therefore, P(X = 18) = 0.25

(b) P(X > 18) = 1 - P(X = 18) - P(X = 13) = 1 - 0.25 - 0.22 = 0.53

(c) P(X <= 18) = P(X = 13) + P(X = 18) = 0.22 + 0.25 = 0.47

(d) Mean of X, \mu = ∑X * P(x) ÷ ∑P(x) = (2.86 + 4.5 + 4 + 4.08 + 4.32) ÷ 1

                                                         = 19.76

(e) Variance of X, \sigma^{2} = ∑X^{2} * P(x) - (\sum X * P(x))^{2}

                                 = 412.74 - 19.76^{2} = 22.2824

(f) Standard deviation of X, \sigma = \sqrt{variance} = \sqrt{22.2824} = 4.7204 .

8 0
3 years ago
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