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3 years ago

What is the measure of ∠ADC?

Mathematics

2 answers:

Pachacha [2.7K]3 years ago

4 0

Answer:

131

Step-by-step explanation:

Serga [27]3 years ago

4 0

Answer:

The angle measure is 131

Step-by-step explanation:

It's 131 because you add angle ADB and angle BDC which will give you the angle measurement 131 . If it is the length measurement, then there isn't enough information.

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Wanni cycled 6 km from her house to the school at a uniform speed, v km/h. If she increased her speed

Karolina [17]

Answer:

The quadratic equation in terms of v is v² + 2 v + 180 = 0

Step-by-step explanation:

Given as :

The distance between house to the school = d = 6 km

The uniform speed = v km/h

So, Time = $\dfrac{\textrm Distance}{\textrm speed}$

or, t = $\dfrac{\textrm d}{\textrm v}$

Or, t = $\dfrac{\textrm 6}{\textrm v}$

<u>Now, Again</u>

The speed is increase by 2 km/h

i.e speed = (v + 2) km/h

So, Time taken = t' = (t - $\dfrac{4}{60}$ )hours

i.e t' = (t - $\dfrac{1}{15}$ )hours

Now, Time = $\dfrac{\textrm Distance}{\textrm speed}$

So, (t - $\dfrac{1}{15}$ ) = $\dfrac{\textrm d}{\textrm v}$

Or, (t - $\dfrac{1}{15}$ ) = $\dfrac{\textrm 6}{\textrm (v + 2)}$

Or , $\dfrac{\textrm 6}{\textrm v}$ - $\dfrac{1}{15}$ = $\dfrac{\textrm 6}{\textrm (v + 2)}$

Or , $\dfrac{\textrm 90 - v}{\textrm 15 v}$ = $\dfrac{\textrm 6}{\textrm v + 2}$

Or, (90 - v) × (v + 2) = 6 × 15 v

Or, 90 v - 180 - v² - 2 v = 90 v

Or, v² + 2 v + 180 = 90 v - 90 v

Or, v² + 2 v + 180 = 0

So, The quadratic equation in terms of v

v² + 2 v + 180 = 0

Hence The quadratic equation in terms of v is v² + 2 v + 180 = 0 Answer

3 0

3 years ago

PLEASE HELPPPP !!!!!!!!!

Brilliant_brown [7]

Answer:

negative 7

Step-by-step explanation

3 0

3 years ago

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a city is building bike racks for people who ride their bikes to work and around town. the city will have 47 bike racks with roo

mina [271]

The city's racks can hold 752 bikes.

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3 years ago

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You own three different rings. You wear all three rings, but no two of the rings are on the same finger, nor are any of them on

Eddi Din [679]

Answer:

Therefore you can wear your rings in =336 ways

Step-by-step explanation:

Multiplication Law: If one occurs in x ways and second event occurs in y ways.Then the number of ways that two event occur in sequence is xy

Given that you have 3 different rings.

We have total 10 figures.

But you don't wear ring on your thumbs.

We have 2 thumbs.

So you can wear rings on (10-2) = 8 figures.

The ways of wearing of first ring is = 8

The ways of wearing of second ring is = 7

The ways of wearing of third ring is = 6

Therefore you can wear your rings in =(8×7×6)

=336 ways

4 0

3 years ago

The side of one square is equal to 3m and its diagonal is equal to the side of a second square. Find the diagonal of the second

navik [9.2K]

Answer:

Step-by-step explanation:

the side of first square = 3 m

area of first square = 3^2= 9 m^2

let the side of second square = x m

since diagonal of first square = x m as per the question

in a square each angle is 90 degree

therefore by applying pythagorus theorem ,

diagonal ^2 = side^2 + side ^2

diagonal^2 = 3^2+3^2=9+9

DIAGONAL= square root of 18

diagonal= 3 $\sqrt{2}$ m = side of second square

therefore in second square ,

one angle is 90 degree , therefore by applying pythagorue theorem

diaqonal^2 = side ^2 + side ^2 = (3 $\sqrt{2}$ )^2 + ( 3 $\sqrt{2}$ )^2

diagonal ^2 = 18 + 18

diagonal = square root of 36

therefore diagonal of second square is 6m

hope it helps you... please mark me as the brainliest..

8 0

3 years ago

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