1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andreyy89
4 years ago
12

Without performing division, determine if the integer 890967 is divisible by 9

Mathematics
1 answer:
ycow [4]4 years ago
4 0
A number is divisible by 9<span> if the sum of its digits is </span><span>divisible by 9 

here the sum 39 not divisible by 9 </span>
You might be interested in
Find the value of c so that the polynomial p(x) is divisible by (x-3). p(x) =-x^3+cx^2-4x+3. c=?
Vilka [71]

Answer:

\boxed{\textsf {The value of c is $\sf \dfrac{-14}{3}$. }}

Step-by-step explanation:

A polynomial is given to us . We need to find the value of c so that it is divisible by (x-3 ) .The given polynomial to us is ,

\sf \implies p(x)=- x^3+cx^2-4x+3

And the factor is ,

\sf \implies g(x) = x + 3

Now , according to factor theorem , p(x) will be divisible by g(x) if p(-3) = 0

\sf \implies p(x)= - x^3+cx^2-4x+3 \\\\\implies\sf p(-3) = 0 \\\\\sf\implies -(-3)^3+c(-3)^2-4(-3)+3 = 0 \\\\\sf\implies 27 + 9c +12+3=0 \\\\\sf\implies 9c +42=0 \\\\\sf\implies 9c = (-42) \\\\\sf\implies c = \dfrac{-42}{9}\\\\\sf\implies \boxed{\pink{\sf c = \dfrac{-14}{3}}}

<h3><u>Hence </u><u>the </u><u>value </u><u>of </u><u>c </u><u>is </u><u>(</u><u>-</u><u>1</u><u>4</u><u>)</u><u>/</u><u>3</u><u> </u><u>.</u></h3>
4 0
3 years ago
Two buses leave towns 304 miles apart at the same time and travel toward each other. One bus travels 14 mih slower than the othe
8090 [49]

Answer:

The faster bus moves at 83mi/h and the slower one moves at 69mi/h.

Step-by-step explanation:

Let's define:

R₁ = rate of bus 1, this is the faster one.

R₂ = rate of bus 2, this is the slower one.

We know that one bus travels 14mi/h slower, then:

R₂ = R₁ - 14mi/h.

Now we know that:

Distance = Speed*Time.

If we add the distances that both busses travel in 2 hours, it should be equal to the initial distance between the buses, then:

R₁*2h + R₂*2h = 304 mi

Then we have the two equations:

R₂ = R₁ - 14mi/h

R₁*2h + R₂*2h = 304 mi

The first step is to replace the first equation in the second one, to get:

R₁*2h + (R₁ - 14mi/h)*2h = 304 mi

And now we can solve this for R₁.

R₁*2h + R₁*2h - 14mi/h*2h = 304 mi

R₁*4h - 28mi = 304mi

R₁*4h = 304mi + 28mi = 332mi

R₁ = 332mi/4h = 83mi/h

The faster bus moves at 83mi/h

And we know that the slower one moves at 14mi/h slower than this, then:

R₂ = R₁ - 14mi/h = 83mi/h - 14mi/h = 69 mi/h

7 0
2 years ago
I dont know this.......
Rashid [163]

Answer: 16

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Last week bananas costed 0.79 per pound this week they cost 0.89 per pound
kirza4 [7]

Answer:

10 cent increase

Step-by-step explanation:

0.89

<u>-0.79</u>

0.10

or 7.89%

8 0
2 years ago
A rectangular prism has a length of 1 yards, a width of 2) yards, and a height of 4 yards.
atroni [7]

Answer:

8

Step-by-step explanation:

2*1*4=8

5 0
3 years ago
Other questions:
  • Solve this equation 3x-√6y=3​
    6·1 answer
  • How do you solve this 13c&lt;-169
    14·1 answer
  • finding the amplitude, period, asymptotes, reflections, vertical shifts, and phase shifts of trig equations
    9·1 answer
  • The ratio of the corresponding linear measures of two similar cans of vegetables is 2 to 3. The smaller can has a surface area o
    6·1 answer
  • O) Simplify the expression.<br> 1 - 14 =
    14·1 answer
  • PLEASE HELP ME FIND THE LENGTH
    8·2 answers
  • Graph the equation.<br> y= 3 | x | + 3
    11·1 answer
  • How many different committees can be formed from 8 teachers and 39 students if the committee consists of 2 teachers and 4 studen
    9·1 answer
  • Shin godzilla vs zilla​
    6·2 answers
  • What is the slope of the line that goes through the points (-1, 4) and (2, 10)​
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!