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Vedmedyk [2.9K]
3 years ago
8

The results of a survey show that the percent of students in an Algebra II class who want to have their grades scored on a curve

is in the interval [48.2, 56.4].
a. What is the point estimate for the percent who want to have their grades scored on a curve?
b. What is the poll’s margin of error?
c. Do you think their class should have their grades scored on a curve? Which statistic influenced your answer the most? Explain.
Mathematics
1 answer:
Hoochie [10]3 years ago
5 0
A. The point estimate would be the average of the interval boundaries, which is the average of 48.2 and 56.4. This gives a point estimate of 52.3%.
b. The margin of error is the distance from either interval boundary to the point estimate. 56.4 - 52.3 = 4.1%.
c. Assuming this is solely going to be based on the class' decision, their grades should be scored on a curve. Although the margin of error is high and this seems to not have a significant distance from 50%, there is no "middle ground" in this option. We must either grade on a curve or not, and if we must choose one, we have to use to point estimate that is just slightly above 50%.

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Find UV (Pic Stated Below)
natta225 [31]

Answer:

UV=29

Step-by-step explanation:

In right triangles AQB and AVB,

∠AQB = ∠AVB ...(i)  {Right angles}

∠QBA = ∠VBA ...(ii)  {Given that they are equal}

We know that sum of all three angles in a triangle is equal to 180 degree. So wee can write sum equation for each triangle


∠AQB+∠QBA+∠BAQ=180 ...(iii)

∠AVB+∠VBA+∠BAV=180 ...(iv)


using (iii) and (iv)

∠AQB+∠QBA+∠BAQ=∠AVB+∠VBA+∠BAV

∠AVB+∠VBA+∠BAQ=∠AVB+∠VBA+∠BAV  (using (i) and (ii))

∠BAQ=∠BAV...(v)


Now consider triangles AQB and AVB;

∠BAQ=∠BAV  {from (v)}

∠QBA = ∠VBA {from (ii)}

AB=AB  {common side}

So using ASA, triangles AQB and AVB are congruent.

We know that corresponding sides of congruent triangles are equal.

Hence

AQ=AV

5x+9=7x+1

9-1=7x-5x

8=2x

divide both sides by 2

4=x

Now plug value of x=4 into UV=7x+1

UV=7*4+1=28+1=29

<u>Hence UV=29 is final answer.</u>

7 0
3 years ago
5x+3y&gt;_ 9 <br> ^<br> This sign is supposed to be greater than Or equal to. Sorry.
Andre45 [30]
It’s saying the equation is going to be equal to.

HOPE THIS HELPS
5 0
3 years ago
How do you find area and perimeter of a rectangle with the side lengths of 5x^2 and 12x?
valentinak56 [21]

Answer:

The area can be found by multiplying the two terms, and the perimeter by doubling and adding them.

Using this, we find that the area of the rectangle is 60x³, and the perimeter is 10x² + 24x.

Step-by-step explanation:

First let's find the area:

5x² × 12x

= 60x³

Now the perimeter:

2(5x² + 12x)

= 10x² + 24x

8 0
3 years ago
Im not sure how to solve this please help
Effectus [21]
Look at the corresponding angle to 82, which is to the left of line b

It also measures 82 according to "corresponding angle theorem"


Then
angle x is equal to it as they are vertical pair of angle

so that, the measure of x equals 82 degree

I hope that helps
5 0
3 years ago
Please I need help PLEASE​
frutty [35]

Answer:

15/2.5  18/h

Step-by-step explanation:

5 0
3 years ago
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