Answer:

Step-by-step explanation:


















Hence, the correct answer is 
16 I just know that it's 16 GL to ya
Sadly, you didn't give me any choices to choose from.
y² - 1 = 24
Add 1 to each side :
y² = 25
y = √25
<u>y = +5</u>
and
<u>y = -5</u>
Answer:
OPTION D
Step-by-step explanation:
We have to determine which option determines the function given above.
To determine the function, just substitute the values and compare LHS and RHS.
we have 



Here,
is the domain and
is the co-doamin.
Therefore, 
Now, OPTION A: 
Substitute x = 4. We get f(x) = 3
18.
So, OPTION A is rejected.
Similarly, OPTION B: 
Substitute x = 4. We get f(4) = 22
18.
It is rejected as well.
Now, for OPTION C: 
Substitute x = 4. We get f(4) = -3
18.
So, OPTION C is also rejected.
OPTION D: 
Substitute x = 4. We get f(4) = 18.
Substitute the remaining points in domain as well. We notice that it exactly matches the given function. So, OPTION D is the answer.
Answer:
2.90m
Step-by-step explanation:
I hope this is the answer.