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Dima020 [189]
3 years ago
13

How to solve this linear equation 2/3y=-12

Mathematics
1 answer:
Alenkinab [10]3 years ago
5 0
Well you are solving for Y so you have to get y by itself. So in order to do that you must multiply both sides by 3/2. You do this because you need to get 2/3 on the other side. So just multiply -12 and 2/3 and you'll get y=-18. You can check this by plugging -18 into your original equation. So 2/3y=-12 will become 2/3(-18)=-12. If the you got the correct answer then you should get -12=-12.
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5 0
3 years ago
Find the rectangular coordinates of the point ( -3, 1/2 π)
alexdok [17]

Answer:

x = -3 cos (\frac{\pi}{2})= 0

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And then the rectangular coordinates for this case are :

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Step-by-step explanation:

We have the following point given P = (-3, \frac{\pi}{2}) and we want to conver from polar to rectangular coordinates and we need to use the following formulas:

x = r cos \theta

y = r sin \theta

For this case we have that:

r = -3

And:

\theta = \frac{\pi}{2}

Replacing we got:

x = -3 cos (\frac{\pi}{2})= 0

y = -3 sin (\frac{\pi}{2})= -3

And then the rectangular coordinates for this case are :

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4 0
3 years ago
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8 0
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3 0
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Read 2 more answers
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8 0
3 years ago
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