Answer:
Each FADH2 yields about 1.5 ATP via oxidative phosphorylation.
Explanation:
Most of the ATP molecules are produced by oxidative phosphorylation, not by substrate-level phosphorylation. During glycolysis, 2 ATP molecules per glucose are produced by substrate-level phosphorylation. Similarly, Kreb's cycle also yields 2 ATP per glucose by substrate-level phosphorylation.
For each pair of electrons transferred to O2 from FADH2 via electron transport chain, 4 and 2 protons are pumped from matrix towards the intermembrane space by complex III and complex IV respectively. It generates the proton concentration gradient required to drive the synthesis of 1.5 ATP molecules. Since oxidation of FADH2 is coupled to the phosphorylation of ADP to form ATP, the process is called oxidative phosphorylation.
Feces are deposited on the ground, and the bacteria in the soil breaks it down, and uses the nutrients
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Answer:
- If individual III-1 marries an unaffected, non-carrier female, none of their children will have DMD
Explanation:
From the options, the only correct statements is that <em>If individual III-1 marries an unaffected, non-carrier female, none of their children will have DMD</em>
<u>DMD is an X-linked recessive trait, meaning that a male individual is either affected or unaffected (can never be a carrier). III-1 is unaffected and if he marries an unaffected, non-carrier female, it means that none of their children will have DMD.</u>
All the children of II-4 and II-5 will always come out with DMD because both parents are affected.
Individuals I-1 and II-1 are males. A male can never be a carrier in for X-linked traits. He is either affected or unaffected and as shown by the pedigree, both males are unaffected (unshaded).