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Vlad1618 [11]
3 years ago
5

How do I do this Hdhdhsuhss

Mathematics
2 answers:
enyata [817]3 years ago
8 0

Answer:

C

Step-by-step explanation:

When the last value changes (but its still at the same position), the median remains unchanged

On the other hand, since the data value has increased, the sum of all values will also increase, thereby increasing the mean

mina [271]3 years ago
3 0

Answer:

The mean will change, the median will stay the same.

Step-by-step explanation:

The mean will increase because that is the average and a gain of 1000 kg will increase that average.

The median will not change.   The median is the middle point.  That was the highest point before and increasing it will not change that it was the highest point.

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Find the lateral area of the come in terms of pi.
Norma-Jean [14]
The answer should be 12x cm power of 2
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Help With This Question ASAP!!!​
ch4aika [34]

Answer:

43.25-7-(t*1.15)

Step-by-step explanation:

because oBaMa

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3 years ago
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JK=2X KL=X+2 and JK=5X-10
elixir [45]

JK + KL = JL

JK = 2x, KL = x + 2, JL = 5x - 10

therefore we heve the equation:

2x + (x + 2) = 5x - 10

3x + 2 = 5x - 10 |-2

3x = 5x - 12 |-5x

-2x = -12 |:(-2)

x = 6

JK = 2x → JK = 2(6) = 12

KL = x + 2 → KL = 6 + 2 = 8

JL = 5x - 10 → JL = 5(6) - 10 = 30 - 10 = 20

Check:

JK + KL = JL

12 + 8 = 20 CORRECT :)

5 0
3 years ago
Colin has a pad with x pieces of paper on it. For his first class, he wrote on 5 fewer than half of the pieces of paper in the p
PIT_PIT [208]

Answer:

Colin has <em>8 sheets </em>left for his third class.

Step-by-step explanation:

Given that:

Total Number of pieces of papers = x

Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad

Writing the equation:

\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8

So, the answer is:

Colin has <em>8</em> <em>sheets </em>left for his third class.

5 0
3 years ago
Please help What is the domain of the following function?
enot [183]

Answer:

Let's use these two sets given to explain what is the domain.

Each value from the left set is x, and from the right is f(x).

If we plug any x from the left set in the function, we'll get f(x)  that corresponds to it and that's exactly what the arrows are showing.

Domain of the function is, basically, a set of all values x can have.

In this case, it's easy to see, those are all members of the left set (-6, 1, 5, 8), but sometimes this set can have lots and lots of members, even infinity.

8 0
3 years ago
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