Answer:
<h2>A and C.</h2>
Step-by-step explanation:
From the problem, we deduct that the function has to be quadratic, because it's mention two zeros, which is proper of a polynomial expression with grade 2.
So, we can say that:

Because, 5 and 0 are roots of the expression.
Also, we know that the point
is on the curve, this means:

Replacing this relation in the first expression, we have:


So, the expression would be:



If we graph, we could get the vertex easier.
You can see in the image, that the vertex is at x = 2.5
Therefore, the option C is the answer.
However, the first option has this function:
h(x) = –0.25(x)(x – 5).
Which also can be solution, because, if we try x = 4:
h(4) = –0.25(4)(4 – 5)=1
Therefore, option A is also part of the answer.