Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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The tank with Chemical X "takes up" a space of 25ft³. Ordinarily we think of something "taking up" space as being area or surface area; however, area is a square measurement, and this is cubic; this must be volume. The volume of the tank with Chemical X is 1.5 times the volume of the tank containing Chemical Y; setting this up in an equation we would have
25 = 1.5<em>V</em>
We would divide both sides by 1.5 to get the volume of the tank containing Chemical Y:
To find the volume of a cylinder, we find the base area and multiply by the height. We know the volume and we know the base area, so our equation to find the height of the tank containing Chemical Y would look like:
We would now divide both sides by 3 2/10:
This is the same as:
So the height of the tank containing Chemical Y is 500/96 = 5 5/24 feet.
<span>6 bags of plaster do 33m2
5 bags .........................?
33 * 5 / 6 = 27.5
answer: 27.5</span><span>m2</span>
Answer:
11. c
12. c
Step-by-step explanation:
11. Since Angle RST = 60 degrees, Angle RTS = 60 degrees.
Triangle STU is a right triangle, so Angle STU and Angle SUT are both 45 degrees.
Angle RTS + Angle STU + Angle UTQ = 180 degrees
60 + 45 + Angle UTQ = 180
Angle UTQ = 180 - 105
= 75 degrees
12. Using the corresponding angles theorem, x = 45 degrees and y = 35 degrees.
x + y
45 + 35
80
Answer:
a= ft is the unit
b=g(gram) is the unit
c= percent % is the answer
