Answer:

Step-by-step explanation:
![\sf h(x) = 5x+2\\\\Put \ h(x) = -8\\\\-8 = 5x+2\\\\Subtract \ 2 \ to \ both \ sides\\\\-8-2 = 5x\\\\-10 = 5x\\\\Divide\ both \ sides \ by \ 5\\\\-10 / 5 = x \\\\x = -2 \\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20h%28x%29%20%3D%205x%2B2%5C%5C%5C%5CPut%20%5C%20h%28x%29%20%3D%20-8%5C%5C%5C%5C-8%20%3D%205x%2B2%5C%5C%5C%5CSubtract%20%5C%202%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C-8-2%20%3D%205x%5C%5C%5C%5C-10%20%3D%205x%5C%5C%5C%5CDivide%5C%20both%20%5C%20sides%20%5C%20by%20%5C%205%5C%5C%5C%5C-10%20%2F%205%20%3D%20x%20%5C%5C%5C%5Cx%20%3D%20-2%20%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
Renae owes 15.55 more.
Step-by-step explanation: 40.75 - 25.20 = 15.55
Answer:
There are 16 squares and 12/16 is 75 percent so 75% - green
25% - white hope this helps :)
Step-by-step explanation:
The original price is 100% of the price. If the price is marked 60% off, then you pay 40% of the original price.
An item costs x dollars.
With the 60% off discount, it now costs 40% of x, or 0.4x.
Now you apply a 30% discount.
For the second discount, consider the price 0.4x to be the new original price. If the price is now discounted 30%, you will pay 70% of the new original price.
Start with 0.4x.
Now calculate 70% of 0.4x.
70% of 0.4x = 0.70 * 0.4x = 0.28x
After applying the 60% discount and the 30% discount, the item that originally cost x now costs 0.28x. 0.28x is the same as 28% of x. The amount you pay is 28% of the original price.
Answer: 28%
Answer:
b.
Step-by-step explanation:
We have to look at sign changes in f(x) to determine the possible positive real roots.

There is only one sign change here, between the -8x and the +4. So that means there is only 1 possible real positive root.
Now we have to look at sign changes in f(-x) to determine the possible negative real roots.

There are 3 sign changes here. That means there are either 3 negative roots or 3-2 = 1 negative root. So we have:
1 positive
3 or 1 negative
We need to pair them up now with all the possible combinations.
If we have 1 positive and 1 negative, we have to have 2 imaginary
If we have 1 positive and 3 negative, we have to have 0 imaginary
Keep in mind that the total number or roots--positive, negative, imaginary--have to add up to equal the degree of the polynomial. This is a 4th degree polynomial, so we will have 4 roots.