All categories

3 years ago

Bella can bake 15 cookies with each scoop of flour. With 3 scoops of flour, how many cookies can Bella bake?

2 answers:

7 0

I think the answer might be 45 because she can bake 15 cookies with each scoop of four. If she uses 3 scoops it will be 15 • 3. So 45 I’m guessing I might be wrong

olya-2409 [2.1K]3 years ago

7 0

Answer:

45 cookies

Step-by-step explanation:

1 scoop/15 cookies = 3 scoops/x cookies.

3•15 = 45, 1•x = x

x = 45 cookies

You might be interested in

CHORES Wayne raked 30 bags of leaves in 3 hours. If he raked the same number of bags each hour, how many bags of leaves did he r

zubka84 [21]

divide total bags by number of hours

30 bags / 3 hors = 10 bags per hour

he racked 10 bags per hour

7 0

3 years ago

Read 2 more answers

Will give brainlisted whoever is correct first. please hurry.

kipiarov [429]

Answer:

32.33 <= m

Step-by-step explanation:

Since we are dealing with below sea level our initial starting point and max level will both be negative values, while our descending rate will also be negative because we are going down. Using the values provided we can create the following inequality...

-400 <= -12m - 12

Now we can solve the inequality to find the max number of minutes that the submarine can descend.

-400 <= -12m - 12 ... add 12 on both sides

-388 <= -12m ... divide both sides by -12

32.33 <= m

3 0

2 years ago

The volume of a spherical balloon is increasing at the constant rate of 8 cubic feet per minute. How fast is the radius incresin

OverLord2011 [107]

Answer:

Rate of increase of radius = 0.0064 ft/sec

Rate of increase of surface area = 1.61 $ft^2/sec$

Step-by-step explanation:

Given that:

Rate of change of volume of a spherical balloon = 8 cubic feet per minute

$\dfrac{dV}{dt} = 8 ft^3/min$

Radius, $r$ = 10 feet

To find:

The rate of change of radius at this moment and rate of change of surface area at this moment?

Solution:

First of all, let us have a look at the formula:

$1.\ V = \dfrac{4}{3}\pi r^3\\2.\ A =4\pi r^2$

Now, differentiating the volume and area, we get:

$\dfrac{dV}{dt} = \dfrac{4}{3}\times 3 \pi r^2 \dfrac{dr}{dt}\\\Rightarrow \dfrac{dV}{dt} = 4 \pi r^2 \dfrac{dr}{dt}$

$\dfrac{dA}{dt} = 4\pi \times 2 r \dfrac{dr}{dt}\\\Rightarrow \dfrac{dA}{dt} = 8\pi r \dfrac{dr}{dt}$

$\dfrac{dV}{dt} = 8 = 4\pi r^2 \dfrac{dr}{dt}\\\Rightarrow 8 = 4\times 3.14 \times 10^2 \dfrac{dr}{dt}\\\Rightarrow 2 = 3.14 \times 10^2 \dfrac{dr}{dt}\\\Rightarrow \dfrac{dr}{dt} = 0.0064\ ft/sec$

$\dfrac{dA}{dt} = 8\times \pi \times r \dfrac{dr}{dt}\\\Rightarrow \dfrac{dA}{dt} = 8\times 3.14 \times 10 \times 0.0064\\\Rightarrow \dfrac{dA}{dt} = \bold{1.61 \ ft^2/sec}$