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babunello [35]
3 years ago
7

What is equivalent to 16/81

Mathematics
2 answers:
GaryK [48]3 years ago
5 0
16/81 is equivalent to 32/162
thats because i did 16 times 2 and 81 times 2
hoped it helped
Lady_Fox [76]3 years ago
4 0
There are a lot of things that are equivalent to 16/81.

16/81 = 0.197530864

Or we can keep multiplying 2 to the numerator and denominator:

16/81 = 32/162 = 64/324 = 128/648
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1 point
kolezko [41]

Answer:

6

Step-by-step explanation:

I pretty sure that its 6 if nt sorry

7 0
3 years ago
Factorise this expression as fully as possible 14t^3 x 6t
kupik [55]
14t^3*6t
= (14*6)*(t^3*t)
= (2*7*2*3)*(t*t*t*t)
= 2*2*3*7*t*t*t*t
6 0
3 years ago
Find the measure of WY
Kipish [7]

Answer: WY=4.4 mm

Step-by-step explanation:

WY=WX/2

WY=8.8/2

WY=4.4 mm

6 0
1 year ago
Read 2 more answers
Write an equation of the line with a slope of -3 and y-intercept of 0
klemol [59]

Answer:

y=-3x

Step-by-step explanation:

Slope intercept form is written as y=mx+b, where:

m= slope

b= y-intercept

We know the slope and y intercept already, so simply plug them in:

y=-3x+0

We can remove the +0 because it is redundant, therefore the final answer is:

y=-3x

4 0
3 years ago
Read 2 more answers
Parking spaces at a business school are arranged by a random monthly lottery. there are 3 spaces for every 10 students who want
Alexus [3.1K]

27.034%  
Let's define the function P(x) for the probability of getting a parking space exactly x times over a 9 month period. it would be: 
P(x) = (0.3^x)(0.7^(9-x))*9!/(x!(9-x)!)  
Let me explain the above. The raising of (0.3^x)(0.7^(9-x)) is the probability of getting exactly x successes and 9-x failures. Then we shuffle them in the 9! possible arrangements. But since we can't tell the differences between successes, we divide by the x! different ways of arranging the successes. And since we can't distinguish between the different failures, we divide by the (9-x)! different ways of arranging those failures as well. So P(4) = 0.171532242 meaning that there's a 17.153% chance of getting a parking space exactly 4 times. 
Now all we need to do is calculate the sum of P(x) for x ranging from 4 to 9.

So
 P(4) = 0.171532242
 P(5) = 0.073513818
 P(6) = 0.021003948
 P(7) = 0.003857868
 P(8) = 0.000413343
 P(9) = 0.000019683
  And
 0.171532242 + 0.073513818 + 0.021003948 + 0.003857868 + 0.000413343
+ 0.000019683 = 0.270340902 
 So the probability of getting a parking space at least four out of the nine months is 27.034%
5 0
3 years ago
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