A closed syllable<span> is a </span>syllable<span> that ends with a consonant. The words fan, am, and left have </span>closed syllables<span>. Multi-syllabic words have </span>closed syllables<span> too. For example, a two-</span>syllable<span> word with the vowel-consonant-consonant-vowel pattern may have one or two </span>closed syllables<span>.</span>
Cisco cyber security would classify this email as security threats.
<h3>How do
Cisco cyber security classify email security threats?</h3>
They classify them as:
- Malware Delivery via Spam.
- Credential Theft
- Business Email Compromise, etc.
Note that in the case above, Cisco cyber security would classify this email as security threats
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Answer and Explanation:
I believe its A. Modularity enables multiple programmers to work on a program at the same time..
Let me know if I'm wrong..
<h3>What is a Finite automata?</h3>
A finite state machine (FSM) or finite state automaton (FSA), or simply a state machine, is a mathematical model of computation. It is an abstract machine that can be in exactly one of a finite number of states at any given time. The FSM may change from one state to another in response to some input; the change from one state to another is called a transition. An FSM is defined by a list of its states, its initial state, and the inputs that trigger each transition. Finite-state machines are of two types - deterministic finite-state machines and non-deterministic finite-state machines. A deterministic finite-state machine can be constructed equivalent to any non-deterministic machine.
With that being said, the DFA is equivalent to the expression 10(0+11)0*1 The expression that you've specified requires at least three 1 to be accepted. Breaking it down into parts.
<h3>Writting the automata:</h3>
<em>S0: 1 => S1 ; 1 </em>
<em>S0: 0 => error ; 0 </em>
<em>S1: 0 => S1 ; 10+ </em>
<em>S1: 0 => S2 ; 10(0 </em>
<em>S2: 0 => S2 </em>
<em>S2: 1 => S3 </em>
<em>S3: 1 => S4 </em>
<em>S4: 0 => S4 </em>
<em>S4: 1 => S5 </em>
<em>S5: 1 => S6 (final state) </em>
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The answer to this problem is A, one-to-one.