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mel-nik [20]
4 years ago
7

Which lines are perpendicular to 5x + 4y = 8?

Mathematics
2 answers:
Lilit [14]4 years ago
3 0
Finite Math. Find Any Equation Perpendicular<span> to the </span>Line 5x-4y=8<span>. 5x−4y=8 5 x - 4 y = 8. Choose a point that the </span>perpendicular line<span> will pass through. (0,0) 0 , 0</span>
Nana76 [90]4 years ago
3 0

Answer:

If two lines are penpendicular their slopes has to be reciprocal, satisfying the next condition:

m_{1} * m_{2} = -1

Step-by-step explanation:

First of all we have to obtain the slope of each line, we can do this by reducing the line equation into this form:

y = m*x + b, where m represents the slope.

  • y = \frac{5}{4}x + 2 m=\frac{5}{4}

  1. y = \frac{5}{4}x - \frac{5}{4} \\ m=\frac{5}{4} \\ m_{1}*m =\frac{25}{16}\\NotPerpendicular
  2. y = -\frac{4}{5}x - 3\\ m=-\frac{4}{5}\\ m_{1}*m=-1\\Perpendicular
  3. y =\frac{4}{5}x + 1\\m=\frac{4}{5}\\ m_{1}*m=1\\NotPerpendicular
  4. y =\frac{4}{5}x + 2\\ m=\frac{4}{5}\\m_{1}*m=1\\NotPerpendicular

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Help asap show work
katovenus [111]

Answer:  see below

<u>Step-by-step explanation:</u>

17) 5n - 3 > -2n + 4     and    9 - 4n ≥ -2n + 1

   <u> +2n   </u>    <u> +2n      </u>              <u>    +2n </u>   <u>+2n      </u>

   7n - 3   >     4                    9 - 2n  ≥       1

        +3         +3                  -9                 -9

    7n       >      7                       -2n   ≥     -8

  <u> ÷7     </u>    <u>     ÷7  </u>                   <u> ÷ -2 </u>  ↓  <u> ÷ -2 </u>

          n  >     1         and            n   ≤   4                  

Graph:   o----------------- ·

              1                     4

18) 9k - 2 ≤ 9 + 10k < 9 - 4k

     9k - 2 ≤ 9 + 10k      and     9 + 10k < 9 - 4k

  <u> -10k     </u>    <u>     -10k </u>               <u>       +4k </u>   <u>    +4k  </u>

     -k - 2 ≤ 9                             9 + 14k < 9

   <u>      +2</u>   <u>+2         </u>                 <u> -9          </u>  <u>-9         </u>

     -k      ≤  11                                  14k  <  0

 <u> ÷ -1    </u>   ↓<u> ÷ -1  </u>                      <u>       ÷14 </u>    <u>÷14      </u>

          k  ≥ -11                and               k < 0

Graph:    · -----------------o

              -11                  0    

19) 4 - n ≤ 10 + 5n ≤ 6n + 1

     4 - n ≤ 10 + 5n       and     10 + 5n ≤  6n + 1

   <u>    -5n </u>   <u>      -5n  </u>                 <u>      -6n </u>   <u>-6n     </u>

   4 - 6n ≤ 10                           10  -  n  ≤       1    

  <u>-4        </u>  <u> -4            </u>              <u> -10        </u>    <u>  -10  </u>

        -6n ≤ 6                                    -n ≤   -9

   <u>  ÷ -6   </u>↓ <u>÷ -6     </u>                    <u>    ÷ -1 </u>↓<u> ÷ -1    </u>

           n ≥ -1              and                 n ≥ 9

Graph:    · -----------------→

              -9                  

20) 4p - 5 ≤ 2p + 9 ≤ 4p + 7

     4p - 5 ≤ 2p + 9     and     2p + 9 ≤ 4p + 7

  <u> -2p       </u>   <u>-2p    </u>                 <u> -4p    </u>   <u>-4p      </u>

    2p - 5 ≤         9                -2p + 9  ≤        7    

    <u>      +5   </u>  <u>    +5    </u>             <u>        -9  </u>    <u>     -9  </u>

       2p  ≤       14                   -2p       ≤      -2

   <u>  ÷ 2   </u>   <u>    ÷ 2     </u>               <u>÷ -2    </u> ↓<u>    ÷ -2    </u>

         p ≤       7          and         p    ≥      1

Graph:    · ----------------- ·

              1                    7

6 0
3 years ago
The picture is there​
aliina [53]

Answer:

Step-by-step explanation:

Because CB = 6 cm, we can find CD

Use Triangle CDB.

<BCD = <BCA - <ACD

<BCD = ?

<BCA = 90

<ACD = 60

<BCD = 90 - 60

<BCD = 30

Cos 30 = CD / CB

CD = Cos(30) * BC

CD = 5.196 cm

<A = 90 - ACD

<ACD = 60

<A = 90 - 60

<A = 30

Sin(<A) = CB / AB

AB = CB / sin(<A)

AB = 6 / 0.5

AB = 12

Area =1/2 CD * AB

Area = 1/2 * 5.196 * 12

Area = 31.18

4 0
3 years ago
3^4 + 3 x 5 =<br> (the '^4' is an exponent)
Vesnalui [34]

Answer:

96

Step-by-step explanation:

3^4 = 3*3*3*3 = 9*9= 81

3*5=15

81 + 15 = 96

Hope this helps!!

4 0
2 years ago
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Parallelogram DEFG is transformed to parallelogram VSTU.
nata0808 [166]

A, because a pre-image means an image before its altered, and VSTU would be the image as a result of DEFG being transformed

3 0
3 years ago
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DEFINE ALL OF THESE, ONE SENTENCE EACH, PLEASE
coldgirl [10]

<u>Answers:</u>

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The Kissing Number Problem: It is a sphere packing problem that includes spheres. Group spheres are packed in space or region has kissing numbers. The kissing numbers are the number of spheres touched by a sphere.  

The Unknotting Problem: It the algorithmic recognition of the unknot that can be achieved from a knot. It defined the algorithm that can be used between the unknot and knot representation of a closely looped rope.

The Large Cardinal Project: it says that infinite sets come in different sizes and they are represented with Hebrew letter aleph. Also, these sets are named based on their sizes. Naming starts from small-0 and further, prefixed aleph before them. eg: aleph-zero.

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3 years ago
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