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3 years ago

Which lines are perpendicular to 5x + 4y = 8?

2 answers:

3 0

Finite Math. Find Any Equation Perpendicular to the Line 5x-4y=8. 5x−4y=8 5 x - 4 y = 8. Choose a point that the perpendicular line will pass through. (0,0) 0 , 0

Nana76 [90]3 years ago

3 0

Answer:

If two lines are penpendicular their slopes has to be reciprocal, satisfying the next condition:

$m_{1} * m_{2} = -1$

Step-by-step explanation:

First of all we have to obtain the slope of each line, we can do this by reducing the line equation into this form:

$y = m*x + b$ , where m represents the slope.

$y = \frac{5}{4}x + 2$ $m=\frac{5}{4}$

$y = \frac{5}{4}x - \frac{5}{4} \\ m=\frac{5}{4} \\ m_{1}*m =\frac{25}{16}\\NotPerpendicular$
$y = -\frac{4}{5}x - 3\\ m=-\frac{4}{5}\\ m_{1}*m=-1\\Perpendicular$
$y =\frac{4}{5}x + 1\\m=\frac{4}{5}\\ m_{1}*m=1\\NotPerpendicular$
$y =\frac{4}{5}x + 2\\ m=\frac{4}{5}\\m_{1}*m=1\\NotPerpendicular$

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Find the size of each of the angles marked with letter

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Answer:

angle l = 115

angle k = 115

angle j = 114

angle i = 66

Step-by-step explanation:

angle l = it is opposite to 115 so its the same

angle k = opposite opposing angles with angle l

angle j = 180-66=114 (between 2 parallel lines the sum of 2 angles is 180)

andle i = 180-114=66 (straight line = 180 degrees so subtract angle j to get i)

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1 year ago

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3 years ago

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What is the area of a circle when the circumference is 25 in

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Step-by-step explanation:

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Derek and Mia place two green marbles and one yellow marble in a bag. Somebody picks a marble out of the bag without looking and

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Step-by-step explanation:

With each draw, the probability of selecting a green marble is 2/3 and the probability of selecting a yellow marble is 1/3.

To pick two of the the same color, they can either pick green twice or yellow twice.

P = (2/3)(2/3) + (1/3)(1/3)

P = 5/9

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P = 4/9

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3 years ago

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

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Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$